应该非常简单:我有一个InputStream,我想偷看(不读取)前两个字节,即我希望在偷看之后,InputStream的“当前位置”为0。最好和最安全的方法是什么?
回答 - 正如我所怀疑的,解决方法是将其包装在提供可标记性的BufferedInputStream中。谢谢Rasmus。
答案 0 :(得分:49)
对于一般的InputStream,我会将它包装在BufferedInputStream中并执行以下操作:
BufferedInputStream bis = new BufferedInputStream(inputStream);
bis.mark(2);
int byte1 = bis.read();
int byte2 = bis.read();
bis.reset();
// note: you must continue using the BufferedInputStream instead of the inputStream
答案 1 :(得分:17)
您可能会发现PushbackInputStream非常有用:
http://docs.oracle.com/javase/6/docs/api/java/io/PushbackInputStream.html
答案 2 :(得分:5)
当使用BufferedInputStream时,确保inputStream尚未缓冲,双缓冲将导致一些人很难找到错误。 此外,您需要以不同方式处理读者,转换为StreamReader,如果Reader是缓冲的,缓冲将导致字节丢失。 此外,如果您使用的是Reader,请记住您没有读取字节,而是使用默认编码中的字符(除非设置了显式编码)。 您可能不知道的缓冲输入流的示例是URL URL; url.openStream();
我没有任何关于此信息的参考,它来自调试代码。 我遇到问题的主要案例是从文件读入压缩流的代码。 如果我在开始调试代码时记得正确,那么Java源代码中的注释表明某些事情总是无法正常工作。 我不记得使用BufferedReader和BufferedInputStream的信息在哪里 来自但我认为即使是最简单的测试也会立刻失败。 记住测试一下,你需要标记超过缓冲区大小(BufferedReader与BufferedInputStream不同),当读取的字节到达缓冲区末尾时会出现问题。 请注意,源代码缓冲区大小可能与您在构造函数中设置的缓冲区大小不同。 我这样做了一段时间,所以我对细节的回忆可能有些偏差。 使用FilterReader / FilterInputStream进行测试,将一个添加到直接流,一个添加到缓冲流以查看差异。
答案 3 :(得分:4)
我在这里找到了一个PeekableInputStream的实现:
http://www.heatonresearch.com/articles/147/page2.html
本文中显示的实现的想法是它在内部保留一系列“peeked”值。调用read时,首先从peeked数组返回值,然后从输入流返回值。当您调用peek时,将读取值并将其存储在“peeked”数组中。
由于示例代码的许可证是LGPL,因此可以附加到此帖子:
package com.heatonresearch.httprecipes.html;
import java.io.*;
/**
* The Heaton Research Spider Copyright 2007 by Heaton
* Research, Inc.
*
* HTTP Programming Recipes for Java ISBN: 0-9773206-6-9
* http://www.heatonresearch.com/articles/series/16/
*
* PeekableInputStream: This is a special input stream that
* allows the program to peek one or more characters ahead
* in the file.
*
* This class is released under the:
* GNU Lesser General Public License (LGPL)
* http://www.gnu.org/copyleft/lesser.html
*
* @author Jeff Heaton
* @version 1.1
*/
public class PeekableInputStream extends InputStream
{
/**
* The underlying stream.
*/
private InputStream stream;
/**
* Bytes that have been peeked at.
*/
private byte peekBytes[];
/**
* How many bytes have been peeked at.
*/
private int peekLength;
/**
* The constructor accepts an InputStream to setup the
* object.
*
* @param is
* The InputStream to parse.
*/
public PeekableInputStream(InputStream is)
{
this.stream = is;
this.peekBytes = new byte[10];
this.peekLength = 0;
}
/**
* Peek at the next character from the stream.
*
* @return The next character.
* @throws IOException
* If an I/O exception occurs.
*/
public int peek() throws IOException
{
return peek(0);
}
/**
* Peek at a specified depth.
*
* @param depth
* The depth to check.
* @return The character peeked at.
* @throws IOException
* If an I/O exception occurs.
*/
public int peek(int depth) throws IOException
{
// does the size of the peek buffer need to be extended?
if (this.peekBytes.length <= depth)
{
byte temp[] = new byte[depth + 10];
for (int i = 0; i < this.peekBytes.length; i++)
{
temp[i] = this.peekBytes[i];
}
this.peekBytes = temp;
}
// does more data need to be read?
if (depth >= this.peekLength)
{
int offset = this.peekLength;
int length = (depth - this.peekLength) + 1;
int lengthRead = this.stream.read(this.peekBytes, offset, length);
if (lengthRead == -1)
{
return -1;
}
this.peekLength = depth + 1;
}
return this.peekBytes[depth];
}
/*
* Read a single byte from the stream. @throws IOException
* If an I/O exception occurs. @return The character that
* was read from the stream.
*/
@Override
public int read() throws IOException
{
if (this.peekLength == 0)
{
return this.stream.read();
}
int result = this.peekBytes[0];
this.peekLength--;
for (int i = 0; i < this.peekLength; i++)
{
this.peekBytes[i] = this.peekBytes[i + 1];
}
return result;
}
}