Question

我知道我可以遍历对象的每个级别，但我想要一种更简单的方法。

QueryResult Object
(
    [queryLocator] => 
    [done] => 1
    [records] => Array
        (
            [0] => SObject Object
                (
                    [type] => type_1
                    [fields] => 
                    [sobjects] => Array
                        (
                            [0] => SObject Object
                                (
                                    [type] => type_2
                                    [fields] => 
                                    [sobjects] => Array
                                        (
                                            [0] => SObject Object
                                                (
                                                    [type] => type_3
                                                    [fields] => 
                                                    [sobjects] => Array
                                                        (
                                                            [0] => SObject Object
                                                                (
                                                                    [type] => type_4
                                                                    [fields] => 
                                                                    [sobjects] => Array
                                                                        (
                                                                            [0] => SObject Object
                                                                                (
                                                                                    [type] => type_5
                                                                                    [fields] => 
                                                                                    [Id] => 12345_I_need_this
                                                                                )

                                                                        )

                                                                )

                                                        )

                                                )

                                        )

                                )

                        )

                )

        )

    [size] => 1
)

我需要type_5的Id值，我怎么能在一个简单的解决方案中得到它。

要考虑的其他一些要点：

我不知道数组的对象有多大或多深，可能多于或少于5

我听说过递归但是没有找到任何我认为可以使用的东西，这样可以保持简单。也许一些更好的教程会帮助我。如果我确实知道对象数组的哪一部分我可以直接调用它？类似于：$ object [5] - ＆gt; id ???

Answer 1

这很简单：

class SObject{
/*...*/

    public getId(){
        if(isset($this->Id)){
            return $this->Id;
        } else {
            return $this->sobjects[0]->getId();
        }
    }
}

你打电话

$id = $query_obj->getId();

Answer 2

以下是递归的工作原理（通常）

function recursiveFunctionName( input ) // returns value;
{
    //Do something to input to make it new_input

    if( isSomethingAccomplished )
    {
        return value;
    }
    else
    {
        return recursiveFunctionName( new_input );
    }
}

您从输入开始，并告诉函数继续调用自身，直到它可以返回有效输出。在你的情况下，你可以这样做：

function getID( SObject $so )
{
    // equates to isSomethingAccomplished...  You have found the value
    // you want returned, so pass that out.
    if( $so->id )
    {
        return $so->id;
    }
    else
    {
        // otherwise, this will return the value from the next level, 
        // pass that out.
        # SEE BELOW FOR ONE MORE NOTE HERE.
        return getID( $so->sobjects[ 0 ] );
    }
}

现在，由于您正在使用数组进行对象，您可能需要使用以下内容替换#SEE BELOW下面的行：

$objs  = $so->sobjects;
$count = count( $objs );

// Iterate through all of its children, testing each of the child nodes.
// (You're actually using iteration and recursion in combination here).
for( $i = 0; $i < $count; $i++ )
{
    $curr = getID( $objs[ $i ] );

    // This is the same test as above.
    if( $curr )
    {
        return $curr;
    }
}

Answer 3

如果您需要在此结构上进行大量查询，请将其转储为XML并在其上使用XPATH

PHP从多级对象获取值的简单方法

3 个答案: