Question

我要搜索JavaScript多级数组对象。

[{ “ head”：“标题1”， “列表”：[{ “ name”：“名称1”， “ desc”：“ desc 1” }，{ “ name”：“名称1”， “ desc”：“ desc 1” }] }，{ “ head”：“标题2”， “列表”：[{ “ name”：“名称1”， “ desc”：“ desc 1” }，{ “ name”：“名称1”， “ desc”：“ desc 1” }] }]

如果我们搜索“标题2”

预期结果：

[{ “ head”：“标题2”， “列表”：[{ “ name”：“名称1”， “ desc”：“ desc 1” }，{ “ name”：“名称1”， “ desc”：“ desc 1” }] }]

如果我们搜索“名称1”

预期结果：

[{ “ head”：“标题1”， “列表”：[{ “ name”：“名称1”， “ desc”：“ desc 1” }，{ “ name”：“名称1”， “ desc”：“ desc 1” }] }，{ “ head”：“标题2”， “列表”：[{ “ name”：“名称1”， “ desc”：“ desc 1” }，{ “ name”：“名称1”， “ desc”：“ desc 1” }] }]

寻找一种优化的方式进行此搜索。谁能帮助我解决这个问题？

已更新：无效的JSON格式

Answer 1

您可以递归搜索给定对象的嵌套值的所需值。

function filter(array, value) {
    function find(object) {
        return Object
            .values(object)
            .some(v => v === value || v && typeof v === 'object' && find(v));
    }

    return array.filter(find);
}

var array = [{ head: "Heading 1", list: [{ name: "name 1", desc: "desc 1" }, { name: "name 1", desc: "desc 1" }] }, { head: "Heading 2", list: [{ name: "name 1", desc: "desc 1" }, { name: "name 1", desc: "desc 1" }] }]

console.log(filter(array, "Heading 2"));
console.log(filter(array, "name 1"));

.as-console-wrapper { max-height: 100% !important; top: 0; }

JavaScript数组对象多级搜索值

1 个答案: