在Django中,我如何知道当前登录的用户?
答案 0 :(得分:106)
您需要在哪里了解用户?
在 views 中,请求中的用户名为request.user
。
对于模板中的用户处理,请参阅here
如果您要保存模型实例的创建者或编辑者,您可以执行以下操作:
model.py
class Article(models.Model):
created_by = models.ForeignKey(User, related_name='created_by')
created_on = models.DateTimeField(auto_now_add = True)
edited_by = models.ForeignKey(User, related_name='edited_by')
edited_on = models.DateTimeField(auto_now = True)
published = models.BooleanField(default=None)
admin.py
class ArticleAdmin(admin.ModelAdmin):
fields= ('title','slug','text','category','published')
inlines = [ImagesInline]
def save_model(self, request, obj, form, change):
instance = form.save(commit=False)
if not hasattr(instance,'created_by'):
instance.created_by = request.user
instance.edited_by = request.user
instance.save()
form.save_m2m()
return instance
def save_formset(self, request, form, formset, change):
def set_user(instance):
if not instance.created_by:
instance.created_by = request.user
instance.edited_by = request.user
instance.save()
if formset.model == Article:
instances = formset.save(commit=False)
map(set_user, instances)
formset.save_m2m()
return instances
else:
return formset.save()
我在互联网上找到了这个,但我不知道在哪里
答案 1 :(得分:6)
扩展@ vikingosegundo的答案,如果你想获得Models中的用户名,我找到了一种涉及声明MiddleWare的方法。在您的应用内创建一个名为get_username.py
的文件,其中包含以下内容:
from threading import current_thread
_requests = {}
def get_username():
t = current_thread()
if t not in _requests:
return None
return _requests[t]
class RequestMiddleware(object):
def process_request(self, request):
_requests[current_thread()] = request
修改您的settings.py
并将其添加到MIDDLEWARE_CLASSES
:
MIDDLEWARE_CLASSES = (
...
'yourapp.get_username.RequestMiddleware',
)
现在,在您的save()
方法中,您可以获得如下的当前用户名:
from get_username import get_username
...
def save(self, *args, **kwargs):
req = get_username()
print "Your username is: %s" % (req.user)
答案 2 :(得分:4)
Django 1.9.6默认项目在默认模板中有user
所以你可以直接写这样的东西:
{% if user.is_authenticated %}
{{ user.username }}
{% else %}
Not logged in.
{% endif %}
此功能由django.contrib.auth.context_processors.auth
中的settings.py
上下文处理器提供。