如何在Django中获取当前登录用户的用户ID?

时间:2012-09-27 06:14:47

标签: django django-models django-authentication

如何获取当前登录用户的ID?

models.py中的

class Game(models.model):
    name = models.CharField(max_length=255)
    owner = models.ForeignKey(User, related_name='game_user', verbose_name='Owner')
views.py中的

gta = Game.objects.create(name="gta", owner=?)

6 个答案:

答案 0 :(得分:158)

首先确保您的SessionMiddleware设置中添加了AuthenticationMiddlewareMIDDLEWARE_CLASSES个中间件。

当前user位于request对象中,您可以通过以下方式获取:

def sample_view(request):
    current_user = request.user
    print current_user.id

request.user将为您提供代表当前登录用户的User对象。如果用户当前未登录,则request.user将设置为AnonymousUser的实例。您可以使用is_authenticated()区分它们,如下所示:

if request.user.is_authenticated():
    # Do something for authenticated users.
else:
    # Do something for anonymous users.

答案 1 :(得分:14)

您可以使用以下代码访问当前登录用户:

request.user.id

答案 2 :(得分:7)

假设您在您的视图中指的是Django的Auth User

def game(request):
  user = request.user

  gta = Game.objects.create(name="gta", owner=user)

答案 3 :(得分:0)

我在ajax视图中编写了此代码,但这是一个更广泛的答案,给出了当前已登录和已注销用户的列表。

is_authenticated属性始终为我的用户返回True,我认为这是预期的,因为它仅检查AnonymousUsers,但是如果要说要在需要登录的地方开发聊天应用程序,那将毫无用处在显示的用户中。

这将检查过期的会话,然后根据已解码的_auth_user_id属性确定会话所属的用户:

def ajax_find_logged_in_users(request, client_url):
    """
    Figure out which users are authenticated in the system or not.
    Is a logical way to check if a user has an expired session (i.e. they are not logged in)
    :param request:
    :param client_url:
    :return:
    """
    # query non-expired sessions
    sessions = Session.objects.filter(expire_date__gte=timezone.now())
    user_id_list = []
    # build list of user ids from query
    for session in sessions:
        data = session.get_decoded()
        # if the user is authenticated
        if data.get('_auth_user_id'):
            user_id_list.append(data.get('_auth_user_id'))

    # gather the logged in people from the list of pks
    logged_in_users = CustomUser.objects.filter(id__in=user_id_list)
    list_of_logged_in_users = [{user.id: user.get_name()} for user in logged_in_users]

    # Query all logged in staff users based on id list
    all_staff_users = CustomUser.objects.filter(is_resident=False, is_active=True, is_superuser=False)
    logged_out_users = list()
    # for some reason exclude() would not work correctly, so I did this the long way.
    for user in all_staff_users:
        if user not in logged_in_users:
            logged_out_users.append(user)
    list_of_logged_out_users = [{user.id: user.get_name()} for user in logged_out_users]

    # return the ajax response
    data = {
        'logged_in_users': list_of_logged_in_users,
        'logged_out_users': list_of_logged_out_users,
    }
    print(data)

    return HttpResponse(json.dumps(data))

答案 4 :(得分:0)

用于模板内

这通常是我在模板中获取当前登录用户及其ID的方式。

<p>Your Username is : {{user}} </p>
<p>Your User Id is  : {{user.id}} </p>

答案 5 :(得分:0)

这通常是我在模板中获取当前登录用户及其ID的方式。

<p>Your Username is : {{user|default: Unknown}} </p>
<p>Your User Id is  : {{user.id|default: Unknown}} </p>