Question

我正在尝试计算每个人在特定目标日期之前和之后的年份中的事件（在event_table中的行）。例如，假设我有一个人100，目标日期是10/01/2012。我想计算9/30 / 2011-9 / 30/2012和10/02 / 2012-9 / 30/2013的活动。

我的查询如下：

select * 
from (
    select id, target_date
    from subsample_table
    ) as i
left join (
   select id, event_date, count(*) as N
        , case when event_date between target_date-365 and target_date-1 then 0 
               when event_date between target_date+1 and target_date+365 then 1
               else 2 end as after 
   from event_table
   group by id, target_date, period
   ) as h
on   i.id = h.id 
 and i.target_date = h.event_date

输出应该类似于：

id  target_date  after  N
100 10/01/2012   0      1000
100 10/01/2012   1      0

有些人可能在之前或之后（或两者）都没有任何事件，在这种情况下拥有零会很好。我不关心730天以外的事件。

任何建议都将不胜感激。

Answer 1

我认为以下内容可能接近您要完成的任务。

   select id
         , target_date
         , event_date
         , count(*) as N
         , SUM(case when event_date between target_date-365 and target_date-1 
                    then 1
                    else 0
                end) AS Prior_ 
         , SUM(case when event_date between target_date+1 and target_date+365 
                    then 1
                    else 0
               end) as After_              
      from subsample_table i
      left join 
           event_table h
        on i.id = h.id 
       and i.target_date = h.event_date
     group by id, target_date, period

Answer 2

这是一个通用的答案。我不知道teradata有什么日期函数，所以我将使用sql server语法。

select id, target_date, sum(before) before, sum(after) after, sum(righton) righton
from yourtable t
join (
select id, target_date td
, case when yourdate >= dateadd(year, -1, target_date) 
  and yourdate < target_date then 1 else 0 end before
, case when yourdate <= dateadd(year, 1, target_date) 
  and yourdate > target_date then 1 else 0 end after
, case when yourdate = target_date then 1 else 0 end righton

from yourtable
where whatever 
group by id, target_date) sq on t.id = sq.id and target_date = dt
where whatever
group by id, target_date

这个答案假设一个id可以有多个目标日期。

计算灵活范围内的事件

2 个答案: