我可以用这种方式进行演员表吗?
int clockOffset;
clockOffset=((int64_t)Time_1_delayed-Time_1-Time_2_delayed+Time_2)/2;
其中所有时间变量均为uint
。
我希望将签名结果放在clockOffset
。
答案 0 :(得分:1)
以下是您可以在C中执行的操作(假设整数和无符号整数比长整数短):
#include <limits.h>
...
unsigned int Time_1_delayed, Time_1, Time_2_delayed, Time_2;
...
long long diff = ((long long)Time_1_delayed - Time_1 - Time_2_delayed + Time_2) / 2;
int clockOffset;
if (diff < INT_MIN || diff > INT_MAX)
HandleTheError();
clockOffset = diff;
...
答案 1 :(得分:0)
你不需要施放。例如,你可以这样做。
uint32_t a = 100;
uint32_t b = 200;
int32_t c = a - b;
你会得到c = -100
。