SQL错误（1111）：组函数的使用无效

Question

我正在尝试在（entrydate列中的最大日期）和（entrydate column-15days中的最大日期）之间获取数据!!

表1：总共有953个

表2：总共有400个

我收到了这个错误，请帮助我!!

    Select  
o_material_transaction_inward.Mat_Code,
s_material_details.Mat_Spec,
s_material_details.Mat_Make,
o_material_transaction_inward.Sup_Name,
o_material_transaction_inward.Entry_Date,
o_material_transaction_inward.DC_qty,
o_material_transaction_inward.Received_qty,
    from 
o_material_transaction_inward 
    join 
s_material_details 
    on 
s_material_details.Mat_Code=o_material_transaction_inward.Mat_Code and s_material_details.Mat_Group_Id=o_material_transaction_inward.Mat_Group_id
    where 
o_material_transaction_inward.Entry_Date between Max(o_material_transaction_inward.Entry_Date) and Max(o_material_transaction_inward.Entry_Date - 15)

Answer 1

更新：已修复BETWEEN谓词：

它不起作用的原因是最低值需要是BETWEEN谓词中的第一个值，所以为了从两个表之间获得entry_date之间的那些行最长入场日期 - 15和最长入场日期试试这个：

SELECT
  o.Mat_Code,
  s.Mat_Spec,
  s.Mat_Make,
  o.Sup_Name,
  DATE_FORMAT(o.Entry_Date, '%Y-%m-%d') AS Entry_Date,
  o.DC_qty,
  o.Received_qty
FROM o_material_transaction_inward AS o
INNER JOIN s_material_details      AS s  ON s.Mat_Code     = o.Mat_Code
WHERE o.Entry_Date BETWEEN ((SELECT Max(Entry_Date) 
                            FROM o_material_transaction_inward) - 15)
                       AND (SELECT Max(Entry_Date) 
                            FROM o_material_transaction_inward) ;

SQL Fiddle Demo

Answer 2

尝试：

    Select  
o_material_transaction_inward.Mat_Code,
s_material_details.Mat_Spec,
s_material_details.Mat_Make,
o_material_transaction_inward.Sup_Name,
o_material_transaction_inward.Entry_Date,
o_material_transaction_inward.DC_qty,
o_material_transaction_inward.Received_qty,
    from 
o_material_transaction_inward 
    join 
s_material_details 
    on 
s_material_details.Mat_Code=o_material_transaction_inward.Mat_Code and s_material_details.Mat_Group_Id=o_material_transaction_inward.Mat_Group_id
    having 
o_material_transaction_inward.Entry_Date between Max(o_material_transaction_inward.Entry_Date) and Max(o_material_transaction_inward.Entry_Date - 15)

（有关where与having的解释，请参阅MySQL: Invalid use of group function的已接受答案）

Answer 3

这应该有效：

SELECT
  o.Mat_Code,
  s.Mat_Spec,
  s.Mat_Make,
  o.Sup_Name,
  o.Entry_Date,
  o.DC_qty,
  o.Received_qty,
FROM o_material_transaction_inward AS o
INNER JOIN s_material_details      AS s  ON s.Mat_Code     = o.Mat_Code
                                        AND s.Mat_Group_Id = o.Mat_Group_id
WHERE o.Entry_Date BETWEEN (SELECT Max(Entry_Date) 
                            FROM o_material_transaction_inward) 
                       AND (SELECT Max(Entry_Date) 
                            FROM o_material_transaction_inward) - 15);