Question

以下查询失败并抱怨#1111 - Invalid use of group function，因为在IF循环中嵌入了两个SUM（）调用。到目前为止，我正在尝试在迁移到另一个SQL查询时实现相同的目标，但我很难有时间，任何人都可以指向正确的方向吗？

数据库由invoices表格组成，如果客户端没有立即支付发票，而是通过安装付款，那么可能会有一些invoices_payments。已知的是，我试图总结所有invoices.invoice_total从其减去每个invoices_payments.payment_date伟驰不等于当前星期只有invoices.issued_date等于当前星期，如果没有的话我试图总结所有invoices_payments.payment_amount其中invoices_payments .payment_date等于当前周。

SELECT
    SUM(

        IF (
            YEARWEEK(i.issue_date, 1) = YEARWEEK(NOW(), 1),
            i.invoice_total,
            0
        )
    ) AS week_invoiced,
    ##SUM Functions embedded inside the next IF are causing error: #1111 - Invalid use of group function
    SUM(

        IF (
            ## If payment is issued on current week
            i.issued_date IS NOT NULL
            AND YEARWEEK(i.issued_date, '%Y%m') = YEARWEEK(NOW(), '%Y%m'),
            ## Sum each invoice.invoice_total and substract each invoices_payments not issued on current week
            SUM(i.invoice_total) - SUM(

                IF (
                    ip.id IS NOT NULL
                    AND YEARWEEK(ip.payment_date, 1) != YEARWEEK(NOW(), 1),
                    ip.payment_amount,
                    0
                )
            ),

        IF (
            ## If payment is not issued on current week
            i.issued_date IS NULL
            OR (
                i.issued_date IS NOT NULL
                AND YEARWEEK(i.issued_date, '%Y%m') != YEARWEEK(NOW(), '%Y%m')
            ),
            ## Sum each invoices_payments issued on current week
            SUM(

                IF (
                    ip.id IS NOT NULL
                    AND YEARWEEK(ip.payment_date, 1) = YEARWEEK(NOW(), 1),
                    ip.payment_amount,
                    0
                )
            ),
            0
        )
        )
    ) AS week_paid,
    SUM(

        IF (
            DATE_FORMAT(i.issue_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m'),
            i.invoice_total,
            0
        )
    ) AS month_invoiced
FROM
    `invoices` AS i
INNER JOIN `currency` AS cur ON i.currency_id = cur.id
LEFT JOIN `invoices_payments` AS ip ON ip.invoice_id = i.id
WHERE
    i.coach_id = 279
AND (
    DATE_FORMAT(i.issue_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
    OR DATE_FORMAT(i.issued_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
    OR (
        ip.id IS NOT NULL
        AND DATE_FORMAT(ip.payment_date, '%Y%m') = DATE_FORMAT(NOW(), '%Y%m')
    )
)
GROUP BY
    i.id

Answer 1

您不需要问题所在的外部SUM。也就是说，内部SUMs就足够了：

SUM( SUM()-SUM() )

- ＆GT;

SUM()-SUM()

＃1111 - 无效使用组功能

1 个答案: