Question

我有一组网址，例如：

https://www.facebook.com/profile.php?id=456789
https://www.facebook.com/messages/78134
https://www.facebook.com/profile.php?id=123
https://www.facebook.com/messages/781234
https://www.facebook.com/45/settings/781234/ab
https://www.facebook.com/48/settings/989213/ef

数据集至少有100个网址，比如5-6种类型。我的期望是：

[
  ['https://www.facebook.com/profile.php?id=456789',
   'https://www.facebook.com/profile.php?id=123'],
  ['https://www.facebook.com/messages/781234',
   'https://www.facebook.com/messages/78134'],
  ['https://www.facebook.com/45/settings/781234/ab',
   'https://www.facebook.com/48/settings/989213/ef']
]

我如何对它们进行分类？没有学习输入。

Answer 1

您的问题没有明确定义，但这似乎符合所需的输出：

require 'uri'

URL_DIVISIONS = %w[profile messages settings]
URL_DIVISION_REGEX = Regexp.union(URL_DIVISIONS)

urls = %w[
  https://www.facebook.com/profile.php?id=456789
  https://www.facebook.com/messages/78134
  https://www.facebook.com/profile.php?id=123
  https://www.facebook.com/messages/781234
  https://www.facebook.com/45/settings/781234/ab
  https://www.facebook.com/48/settings/989213/ef
]

pp urls.group_by{ |url|
  URI.parse(url).path[URL_DIVISION_REGEX] 
}

哪个输出：

{"profile"=>
  ["https://www.facebook.com/profile.php?id=456789",
  "https://www.facebook.com/profile.php?id=123"],
"messages"=>
  ["https://www.facebook.com/messages/78134",
  "https://www.facebook.com/messages/781234"],
"settings"=>
  ["https://www.facebook.com/45/settings/781234/ab",
  "https://www.facebook.com/48/settings/989213/ef"]}

如果您需要没有分隔信息的列表，请使用：

pp urls.group_by{ |url|
  URI.parse(url).path[URL_DIVISION_REGEX] 
}.values

哪个输出：

[["https://www.facebook.com/profile.php?id=456789",
  "https://www.facebook.com/profile.php?id=123"],
["https://www.facebook.com/messages/78134",
  "https://www.facebook.com/messages/781234"],
["https://www.facebook.com/45/settings/781234/ab",
  "https://www.facebook.com/48/settings/989213/ef"]]

我将它保留为散列，并使用URL_DIVISIONS数组循环键，根据需要提取值。

Answer 2

这是一个自学版本。您没有指定学习的确切标准，因此您可能想要调整正则表达式，但也许您可以将其作为起点：

require 'uri'

urls = %w[
  https://www.facebook.com/profile.php?id=456789
  https://www.facebook.com/messages/78134
  https://www.facebook.com/profile.php?id=123
  https://www.facebook.com/messages/781234
  https://www.facebook.com/45/settings/781234/ab
  https://www.facebook.com/48/settings/989213/ef
]

pp urls.group_by { |url|
  (URI.parse(url).path.match(/[a-z]+/) || ["unknown"])[0]
}

输出：

{"messages"=>
  ["https://www.facebook.com/messages/78134",
   "https://www.facebook.com/messages/781234"],
 "profile"=>
  ["https://www.facebook.com/profile.php?id=456789",
   "https://www.facebook.com/profile.php?id=123"],
 "settings"=>
  ["https://www.facebook.com/45/settings/781234/ab",
   "https://www.facebook.com/48/settings/989213/ef"]}

如何对URL进行分类？

2 个答案: