Question

这是另一个'for xml'问题，但我不确定这是否可以在没有显式模式的情况下完成。如果它不能，那么我将不得不忍受它。

以下是我目前的选择陈述：

    SELECT
        [stream_id] as '@stream_id',
        [path_locator] as '@path_locator',
        [parent_path_locator] as '@parent_path_locatr',
        [file_type] as '@file_type',
        [cached_file_size] as '@cached_file_size',
        [creation_time] as '@creation_time',
        [last_write_time] as '@last_write_time',
        [last_access_time] as '@last_access_time',
        [is_directory] as '@is_directory',
        [is_offline] as '@is_offline',
        [is_hidden] as '@is_hidden',
        [is_readonly] as '@is_readonly',
        [is_archive] as '@is_archive',
        [is_system] as '@is_system',
        [is_temporary] as '@is_temporary',
        [name] as '/name',
        dbo.udf_GetChildren(path_locator)
    FROM @Merged
    WHERE path_locator.GetLevel() = 1
    FOR XML PATH'file'), ROOT('files'), TYPE

这将输出以下xml：

 <files>
   <file stream_id="" etc...>
      <name>NAME</name>
   </file>
 </files>

这还不错，但我真正喜欢的是将 name 元素的值作为 file 元素的值。这是一个如此简单的任务，我认为它可以在没有显式模式的情况下完成，但我经常对这些事情做错了。

我尝试使用'/'标记，但这似乎没有我想要的效果（例如Update XML node (in an XML column) in SQL Server 2005 with another column value in the same row）。

修改所需的xml就是这样：

 <files>
   <file stream_id="" etc...>NAME</file>
 </files>

非常感谢你的帮助。

Answer 1

使用name as '*'

Columns with a Name Specified as a Wildcard Character

Answer 2

我认为您必须从字段中删除列名称 - 我能够将空白空间连接到末尾。这是一个浓缩版本，您应该可以使用上面的示例：

SELECT name + ''
FROM TestXML
FOR XML PATH('file')

这是SQL Fiddle。

关于它的好文章：

http://msdn.microsoft.com/en-us/library/bb510469.aspx

以上是您的上述查询：

SELECT
    [stream_id] as '@stream_id',
    [path_locator] as '@path_locator',
    [parent_path_locator] as '@parent_path_locatr',
    [file_type] as '@file_type',
    [cached_file_size] as '@cached_file_size',
    [creation_time] as '@creation_time',
    [last_write_time] as '@last_write_time',
    [last_access_time] as '@last_access_time',
    [is_directory] as '@is_directory',
    [is_offline] as '@is_offline',
    [is_hidden] as '@is_hidden',
    [is_readonly] as '@is_readonly',
    [is_archive] as '@is_archive',
    [is_system] as '@is_system',
    [is_temporary] as '@is_temporary',
    [name] + '',
    dbo.udf_GetChildren(path_locator)
FROM @Merged
WHERE path_locator.GetLevel() = 1
FOR XML PATH'file'), ROOT('files'), TYPE

祝你好运。

Answer 3

我将file节点移到了每一列：

SELECT [stream_id] AS 'file/@stream_id'
   , [is_system] AS 'file/@is_system'
   , [is_temporary] AS 'file/@is_temporary'
   ...
   , [name] AS 'file'
FROM Merged
FOR XML PATH('files'), TYPE;

SQL Server'FOR XML'将值赋入“row”元素节点

3 个答案: