Question

在SQL Server中，我想获取XML对象记录中的第n个（第二个）标记值

declare @xml xml = 
'<animals>
    <dog>
        <petname>fred</petname>
    </dog>
    <cat>
        <petname>bill</petname>
    </cat>
</animals>'

select 
    n.value('petname[1]','varchar(10)') as name,
    n.value('../(*).name()[1]','varchar(10)') as animalType  -- don't know how to get this???
from 
    @xml.nodes('animals/*') as a(n)

我想要的结果：

name   animalType
-----------------
fred   dog
bill   cat

由于

Answer 1

您是否尝试过本地名称？

declare @xml xml = 
'<animals>
    <dog>
        <petname>fred</petname>
    </dog>
    <cat>
        <petname>bill</petname>
    </cat>
</animals>'

select 
n.value('petname[1]','varchar(10)') as name,
n.value('local-name(.)','varchar(10)') as animalType
from @xml.nodes('animals/*') as a(n)

SQL Server XML节点值

1 个答案: