Ajax queryString - 我应该使用哪些变量

时间:2013-01-29 19:52:07

标签: javascript ajax query-string

我看过一个AJAX教程,我认为这是适合我情况的代码。

    <script language="javascript" type="text/javascript">
    <!-- 
     //Browser Support Code
     function ajaxFunction(){
     var ajaxRequest;  // The variable that makes Ajax possible!

     try{
     // Opera 8.0+, Firefox, Safari
     ajaxRequest = new XMLHttpRequest();
     } catch (e){
     // Internet Explorer Browsers
     try{
        ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
      } catch (e) {
        try{
            ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
        } catch (e){
            // Something went wrong
            alert("Your browser broke!");
            return false;
        }
       }
     }
       // Create a function that will receive data sent from the server
      ajaxRequest.onreadystatechange = function(){
      if(ajaxRequest.readyState == 4){
        document.myForm.time.value = ajaxRequest.responseText;
         }
        }
      var age = document.getElementById('age').value;
      var wpm = document.getElementById('wpm').value;
      var sex = document.getElementById('sex').value;
      var queryString = "?age=" + age + "&wpm=" + wpm + "&sex=" + sex;
      ajaxRequest.open("GET", "ajax-example.php" + queryString, true);
      ajaxRequest.send(null); 
      }

      //-->
      </script>

在html主体中有一个表单,其中包含一个包含5行8列的表 包含一个复选框。表格代表音乐厅中的可用座位。 我不知道在queryString中添加哪个或多少个变量,因为用户应该点击随机数量的座位。预订的座位当前在一个数组中:

var booked_seats=new Array();
var c = document.getElementById(form).getElementsByTagName('input');
for (var i = 0; i < c.length; i++) {
    if (c[i].type == 'checkbox' && c[i].checked==true){
        booked_seats[count]=c[i].id;
        count++;

    }

我应该写什么来查询字符串?

0 个答案:

没有答案