警告:排名不足,MATLAB

时间:2013-01-29 14:40:47

标签: matlab matrix

我一直在接受错误陈述:

Warning: Rank deficient, rank = 1, tol =  3.845925e-13. 
In ed1 at 38 

Warning from ed1 at 38
 pf2(i)= length (find(sum((y)/(sqrt(NV))).^2)/(n<Tgam))/1000000;

在命令promopt中运行[y1,y2,y3,y4]= ed1(1,1,20,2);中的以下代码类型。导致此错误的行是pf2(i)pd2(i)

function [y1,y2,y3,y4]= ed1(SNRL,SNRS,SNRH,n) %ed is the energy detection
g1= SNRL:SNRS:SNRH;
g=10.^(g1/10); %SNR
beta=0.8; % is the probability pfa, it cannot be more than 1

pf1=zeros(1,length(g));
pd1=zeros(1,length(g));
pf2=zeros(1,length(g));
pd2=zeros(1,length(g));
x=zeros(n,1000000);
y=zeros(n,1000000);
NV=zeros(n,1000000);

for a= 1:g %diff SNR
for b= 1:n %DIFF USERS,users are columns 
            NV(a,b)=1*b ;%assigning a value to the element of the matrix.
end
end

for i=1 : g %samples

for j=1:n       %diff users. 
 %NV=ones(1000000,n);
    x(j,:)=randn(1,1000000)*sqrt(NV(i,j));  
    y(j,:)=randn(1,1000000)*sqrt(g(i)/NV(i,j))+x(j,:);

end

 %Tgam is the threshold of gamma distribution 
 Tgam = gaminv((1-beta),n/2,(2/n)*(1+(g(i)/NV(i,j)))); %probab of flase detection;


 pf2(i)= length (find(sum((y)/(sqrt(NV))).^2)/(n<Tgam))/1000000;
 pd2(i)= length (find(sum(x/sqrt(NV)).^2)/n<Tgam)/1000000; 

 y1=pf1; y2=pd1; y3=pf2; y4=pd2;
end

是什么原因引起的?请问如何解决。 感谢

2 个答案:

答案 0 :(得分:3)

在第

pf2(i)= length (find(sum((y)/(sqrt(NV))).^2)/(n<Tgam))/1000000;
你真的想进行矩阵划分吗?如果您对元素分割感兴趣(即y的第一个元素除以sqrt(NV)的第一个元素等,则应使用./

pf2(i)= length (find(sum((y)./(sqrt(NV))).^2)/(n<Tgam))/1000000;

答案 1 :(得分:2)

您正在使用/(矩阵右分割),而您可能意味着./(右分割)。

至于错误信息的解释,请参阅EitanT的评论。