从多个模型重新打包查询结果。 Rails的方式

时间:2013-01-28 12:49:57

标签: ruby-on-rails json models

我有一个渲染json的控制器。这是代码:

class AppLaunchDataController < ApiController
    def index
        service_types = []
        vendors = []
        tariffs = []
        fields = []
        vendors_hash = {}
        service_types_hash = {}
        tariffs_hash = {}
        fields_hash = {}

        @service_types = ServiceType.select("title, id").all.each do |service_type|
            service_types_hash = {id: service_type.id, title: service_type.title}
            service_types << service_types_hash
            @vendors = service_type.vendors.select("title, id").all.each do |vendor|
                vendors_hash = {id: vendor.id, title: vendor.title}
                vendors << vendors_hash
                @tariff = vendor.tariffs.select("title, id").all.each do |tariff|
                    tariffs_hash = {id: tariff.id, title: tariff.title}
                    tariffs << tariffs_hash
                    @fields  = tariff.fields.select("id, current_value, value_list").all.each do |field|
                        fields_hash = {id: field.id, current_value: field.current_value, value_list: field.value_list}
                        fields << fields_hash
                    end
                    tariffs_hash[:fields] = fields
                    fields = []
                end
                vendors_hash[:tariffs] = tariffs
                tariffs = []
            end
            service_types_hash[:vendors] = vendors
            vendors = []
        end
        render json: service_types
    end
end

返回值如下所示:

[{"id":1,"title":"Water",
"vendors":[{"id":1,"title":"Vendor_1",
"tariffs":[{"id":1,"title":"Unlim",
"fields":[{"id":1,"current_value":"200","value_list":null},{"id":2,"current_value":"Value_1","value_list":"Value_1, Value_2, Value_3"}]},{"id":2,"title":"Volume",
"fields":[]}]},
{"id":2,"title":"Vendor_2",
"tariffs":[]}]},
{"id":2,"title":"Gas",
"vendors":[]},
{"id":3,"title":"Internet",
"vendors":[]}]

它有效,但我确信还有另一种(更多的轨道)方式来获得结果。 如果有人以前处理过,请帮助。感谢。

1 个答案:

答案 0 :(得分:0)

只需使用

# for eager-loading :
@service_types = ServiceType.includes( vendors: {tariffs: :fields} ) 
# now for the json :
@service_types.to_json( include: {vendors: {include: {tariffs: { include: :fields}}}} )

如果您的ServiceType对象始终具有此类表示,则只需覆盖模型的as_json方法:

class ServiceType
  def as_json( options={} )
    super( {include: :vendors }.merge(options) ) # vendors, etc.
  end
end

鼓励在rails中执行此操作:在模型上调用to_json只会调用as_json,可能还有其他选项。实际上,as_json描述了此模型的规范json表示。有关详情,请参阅to_json上的api dock

如果您的需求更加特殊(使用选择以获得更快的查询),您可以随时在模型上滚动自己的to_json_for_app_launch_data方法(使用或不使用as_json),甚至更好presenter