Question

我有以下用户控制器：

@RequestMapping("/user")
public class UserController {

    private static final String ID = "id";

    private final Log logger = LogFactory.getLog(getClass());

    private UserManager um;

    @Autowired
    public void setUserManager(UserManager userManager) {
        this.um = userManager;
    }

    @RequestMapping(method = RequestMethod.GET)
    public ModelAndView showUser(HttpServletRequest request) {
        User user = null;

        String id = (String) request.getParameter(ID);
        if (id == null) {
            String message = "Cannot find user id";
            logger.error(message);
            return new ModelAndView("WEB-INF/jsp/error.jsp", "message", message);
        }
        try {
            user = (User) um.getUserByUserId(Integer.parseInt(id));
        } catch (Exception e) {
            String message = "Cannot find user with id: " + id;
            logger.error(message);
            return new ModelAndView("WEB-INF/jsp/error.jsp", "message", message);
        }

        logger.info("Returning user view for user id: " + id);
        return new ModelAndView("WEB-INF/jsp/user.jsp", "user", user);
    }


    @RequestMapping(value = "/new", method = RequestMethod.GET)
    public ModelAndView getNewUserForm(Model model) {
        logger.info("Get new user form");
        return new ModelAndView("WEB-INF/jsp/userForm.jsp", "user", new User());
    }

我的所有视图文件都在WEB-INF / jsp /

中

当我尝试转到页面时：localhost：8080 / myapp / user.htm一切正常但是当我尝试转到：localhost：8080 / myapp / user / new.htm我收到错误404页面未找到。

这个代码执行的原因是因为我看到了日志：

@RequestMapping(value = "/new", method = RequestMethod.GET)
        public ModelAndView getNewUserForm(Model model) {
            logger.info("Get new user form");
            return new ModelAndView("WEB-INF/jsp/userForm.jsp", "user", new User());
        }

在404错误页面上是信息： /myapp/user/WEB-INF/userForm.jsp not foud

这是我的问题。如何将其更改为：/myapp/WEB-INF/userForm.jsp？我的请求映射应该怎么办？

Answer 1

看一下关于控制器和返回类型的Spring Documentation。那里有很好的例子，你可以看到很多方法可以使用控制器方法。

在您的情况下，您无需指定视图的完整路径。只是视图名称没问题。

@RequestMapping(value = "/new", method = RequestMethod.GET)
public ModelAndView getNewUserForm(Model model) {
    logger.info("Get new user form");

    return new ModelAndView("userForm", "user", new User());
}

你甚至可以这样做。 Spring允许多种可能性。文档概述了所有这些：

@RequestMapping(value = "/new", method = RequestMethod.GET)
public String getNewUserForm(Model model) {
    logger.info("Get new user form");
    model.addAttribute("user", new User());
    return "userForm";
}

另外，请确保已配置View Resolver。您可以从文档中看到您需要这样的东西。

<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
    <property name="prefix" value="/WEB-INF/jsp/"/>
    <property name="suffix" value=".jsp"/>
</bean>

WEB-INF中的Spring多级url映射

1 个答案: