我有一个数据库,人们可以为不同地方的人提交投票。在某个时间,我想找出每个地方谁拥有最多选票。 (一个人可以在两个不同的地方投票)
这是我到目前为止的SQL:
SELECT placeId, userVotedId, cnt
FROM
(SELECT uvo.userVotedId, p.placeId, count(*) as cnt
FROM users as u, users_votes as uvo, places as p
WHERE u.userId = uvo.userVotedId
AND p.placeId = uvo.placeId
GROUP BY userVotedId, placeId)
AS RESULT
给了我这个结果:
现在,这些是我真正想要的行:
我的查询中缺少什么,所以我可以得到这个?
我想要每个地方一个结果。所以我应该只看到不同的placeIds,其中userVotedId得到的票数最多。
如果出现平局,随机获胜者将会做到!
答案 0 :(得分:3)
好像你还需要一个聚合。在 MAX()
值和cnt
上使用GROUP BY placeId, userVotedId
汇总:
SELECT placeId, userVotedId, max(cnt)
FROM
(
SELECT uvo.userVotedId, p.placeId, count(*) as cnt
FROM users as u
INNER JOIN users_votes as uvo
ON u.userId = uvo.userVotedId
INNER JOIN places as p
ON p.placeId = uvo.placeId
GROUP BY userVotedId, placeId
) AS RESULT
GROUP BY placeId, userVotedId
注意:我将您的查询更改为使用 JOIN
语法而不是表格之间的逗号。
编辑,根据您的评论,以下内容应该有效:
select total.uservotedid,
total.placeid,
total.cnt
from
(
SELECT uvo.userVotedId, p.placeId, count(*) as cnt
FROM users as u
INNER JOIN users_votes as uvo
ON u.userId = uvo.userVotedId
INNER JOIN places as p
ON p.placeId = uvo.placeId
GROUP BY userVotedId, placeId
) total
inner join
(
select max(cnt) Mx, placeid
from
(
SELECT uvo.userVotedId, p.placeId, count(*) as cnt
FROM users as u
INNER JOIN users_votes as uvo
ON u.userId = uvo.userVotedId
INNER JOIN places as p
ON p.placeId = uvo.placeId
GROUP BY userVotedId, placeId
) mx
group by placeid
) src
on total.placeid = src.placeid
and total.cnt = src.mx
结果是:
| USERVOTEDID | PLACEID | CNT |
-------------------------------
| 65 | 11 | 1 |
| 67 | 13 | 1 |
| 67 | 25 | 1 |
| 67 | 51 | 2 |
编辑#2,如果你想要一个平局就返回一个随机数,那么你可以使用用户变量:
select uservotedid,
placeid,
cnt
from
(
select total.uservotedid,
total.placeid,
total.cnt,
@rownum := case when @prev = total.placeid then @rownum+1 else 1 end rownum,
@prev := total.placeid pplaceid
from
(
SELECT uvo.userVotedId, p.placeId, count(*) as cnt
FROM users as u
INNER JOIN users_votes as uvo
ON u.userId = uvo.userVotedId
INNER JOIN places as p
ON p.placeId = uvo.placeId
GROUP BY userVotedId, placeId
) total
inner join
(
select max(cnt) Mx, placeid
from
(
SELECT uvo.userVotedId, p.placeId, count(*) as cnt
FROM users as u
INNER JOIN users_votes as uvo
ON u.userId = uvo.userVotedId
INNER JOIN places as p
ON p.placeId = uvo.placeId
GROUP BY userVotedId, placeId
) mx
group by placeid
) src
on total.placeid = src.placeid
and total.cnt = src.mx
order by total.placeid, total.uservotedid
) src
where rownum = 1
order by placeid, uservotedid
答案 1 :(得分:1)
SELECT placeId, userVotedId, MAX(cnt)
FROM (SELECT uvo.userVotedId, p.placeId, count(*) AS cnt
FROM users as u, users_votes as uvo, places as p
WHERE u.userId = uvo.userVotedId AND p.placeId = uvo.placeId
GROUP BY userVotedId, placeId) AS RESULT
GROUP BY placeId
类似问题 - SQL query max(), count()
答案 2 :(得分:1)
为简单起见,我调用了您的查询测试:
SELECT *
FROM Test T JOIN (
SELECT t.placeId, Max(t.cnt) maxcnt
FROM Test t
GROUP BY t.placeId) T2 ON T.placeId = T2.placeId and T.cnt = T2.maxcnt
这是Fiddle。
BTW - 测试=:
SELECT uvo.userVotedId, p.placeId, count(*) as cnt
FROM users as u
INNER JOIN users_votes as uvo
ON u.userId = uvo.userVotedId
INNER JOIN places as p
ON p.placeId = uvo.placeId
GROUP BY userVotedId, placeId
祝你好运。
- 编辑 - 根据要求,这是最终代码:
SELECT *
FROM (SELECT uvo.userVotedId, p.placeId, count(*) AS cnt
FROM users as u, users_votes as uvo, places as p
WHERE u.userId = uvo.userVotedId AND p.placeId = uvo.placeId
GROUP BY userVotedId, placeId) T JOIN (
SELECT t.placeId, Max(t.cnt) maxcnt
FROM (SELECT uvo.userVotedId, p.placeId, count(*) AS cnt
FROM users as u, users_votes as uvo, places as p
WHERE u.userId = uvo.userVotedId AND p.placeId = uvo.placeId
GROUP BY userVotedId, placeId) t
GROUP BY t.placeId) T2 ON T.placeId = T2.placeId and T.cnt = T2.maxcnt