Question

我正在使用SQL Server 2008 R2。我需要得到Sunday weekno并且我已经有了查询，但它显示了错误的数据。我该怎么办？

它显示2而不是1.例如，2013年1月6日（WeekNo - 1）

我的查询是

SELECT DATEPART (week, '01-13-2013 23:59:59.000' ) As WeekNo1 ,  
  DATEPART (week, '01-06-2013 23:59:59.000' ) As WeekNo2 ,  
  DATEPART (week, '12-30-2012 23:59:59.000' ) As WeekNo3 ,  
  DATEPART (week, '12-23-2012 23:59:59.000' ) As WeekNo4 ,  
  DATEPART (week, '12-16-2012 23:59:59.000' ) As WeekNo5 ,  
  DATEPART (week, '12-09-2012 23:59:59.000' ) As WeekNo6

Answer 1

您需要将DATEFIRST属性设置为一周的开始日期。这指定了一周的第一天。

要确定服务器一周的第一天是什么，您将使用：

SELECT @@DATEFIRST

然后，如果您需要更改该值，请使用：

SET DATEFIRST 1;

SELECT DATEPART (week, '01-13-2013 23:59:59.000' ) As WeekNo1 ,  
  DATEPART (week, '01-06-2013 23:59:59.000' ) As WeekNo2 ,  
  DATEPART (week, '12-30-2012 23:59:59.000' ) As WeekNo3 ,  
  DATEPART (week, '12-23-2012 23:59:59.000' ) As WeekNo4 ,  
  DATEPART (week, '12-16-2012 23:59:59.000' ) As WeekNo5 ,  
  DATEPART (week, '12-09-2012 23:59:59.000' ) As WeekNo6

请参阅SQL Fiddle with Demo。

Answer 2

查询：

<强> SQLFIDDLEExample

SET DATEFIRST 1
SELECT DATEPART (week, '01-13-2013 23:59:59.000' ) As WeekNo1 ,  
       DATEPART (week, '01-06-2013 23:59:59.000' ) As WeekNo2 , 
       DATEPART (week, '12-30-2012 23:59:59.000' ) As WeekNo3 ,  
       DATEPART (week, '12-23-2012 23:59:59.000' ) As WeekNo4 ,  
       DATEPART (week, '12-16-2012 23:59:59.000' ) As WeekNo5 ,  
       DATEPART (week, '12-09-2012 23:59:59.000' ) As WeekNo6

结果：

| WEEKNO1 | WEEKNO2 | WEEKNO3 | WEEKNO4 | WEEKNO5 | WEEKNO6 |
-------------------------------------------------------------
|       2 |       1 |      53 |      52 |      51 |      50 |

我想星期天没有周末？

2 个答案: