Question

这在sql中是否可行？

我有一个包含以下行的表

 StoreID |  Date      | SalesItem |
 1       | 2016-08-16 |  Book    |
 2       | 2016-08-16 | Pen      |
 1       | 2016-08-15 | Pen      |
 1       | 2016-08-15 | Book     |

我想要的结果是

Store | Week | Sales
1     | 11   | 30
2     | 11   | 15

我正在使用sql server 2008，数据集比上面的例子大得多，但这基本上是我想要在sql中实现的，而不是在PHP之后处理。

到目前为止我所拥有的是

 select [DATE], [store], count(store) as total, DATEPART(ww,DATE) 
 AS weeknum from [contracts] where [DATE] >= DATEADD(month, -12, GetDate())
 group by [DATE], [store] order by [DATE] asc

Answer 1

尝试以下代码

    SELECT Store,DATEPART(WW,Date),SUM(Sales) FROM TABLE1
    GROUP BY Store, DATEPART(WW,Date)

根据问题编辑

    SELECT Store,DATEPART(WW,Date),count(Sales) FROM TABLE1
    GROUP BY Store, DATEPART(WW,Date)

MSSQL查询从date，groupby weekno和sum sales获得weekno

1 个答案: