MySQL：在“update”和“where”字段中使用select的结果

Question

我有两个图像表，现在我想将所有图像打包在一个表中并通过外键fk_image引用它：

另外：

Table1: ('id_system' , 'logo_image_raw', 'fk_image')
Table2: ('id_image', 'image_raw_data')

如何将logo_image_raw复制/移动到Table的2'image_raw_data'并在fk_image中反映其id_image？

Answer 1

只需INSERT...INTO SELECT

INSERT  INTO table2 (id_image, image_raw_data)
SELECT  fk_image, logo_image_raw
FROM    table1 

如果列image_raw_data为空但您已经id_image，则需要加入表格，以便获取每个ID的特定图像，

UPDATE  table2 b 
        INNER JOIN table1 a
           ON a.fk_image = b.id_image
SET     b.image_raw_data = a.logo_image_raw

Answer 2

你可以这样做..

 INSERT INTO table2
 SELECT table1.fk_image, table1.logo_image_raw
 FROM table1, table2 WHERE table1.fk_image = table2.id_image