提供商:
SELECT ID,has_account from service_providers where has_account='yes';
+-----+-------------+
| ID | has_account |
+-----+-------------+
| 17 | yes |
| 687 | yes |
| 158 | yes |
| 292 | yes |
| 306 | yes |
| 444 | yes |
| 536 | yes |
| 572 | yes |
| 601 | yes |
| 697 | yes |
+-----+-------------+
帐户:
SELECT ID,active from accounts;
+-----+--------+
| ID | active |
+-----+--------+
| 1 | yes |
| 3 | yes |
| 4 | yes |
| 7 | yes |
| 8 | yes |
| 9 | yes |
| 10 | yes |
| 11 | yes |
| 12 | yes |
| 13 | no |
| 14 | yes |
| 15 | yes |
| 16 | no |
+-----+--------+
我想在mysql中使用它:
if account == active
set provider.has_account == 'yes'
我需要将has_account字段设置为yes id帐户是帐户处于活动状态。
为了保护隐私,我们可以说表格是通过ID
连接的答案 0 :(得分:1)
加入表并使用UPDATE
语句设置字段:
UPDATE providers AS p
JOIN accounts AS a ON p.id = a.id
SET p.has_account = 'yes'
WHERE a.active = 'yes'