Question

有没有办法在Image（手，静脉）中找到分叉点和脊终点，只使用Java代码而不是Matlab等？我可以通过ImageJ Library of Java实现这一目标吗？

Answer 1

您在Minutiae Extraction from Fingerprint Images中找到的科学描述。有些算法在OpenCV中实现，请参阅细分部分。

可以使用JNI将OpenCV库链接到java。

Answer 2

有一个ImageJ插件可以帮助你做到这一点：

AnalyzeSkeleton （来源见here）

您可以借助其SkeletonResult类提取分支点和端点。

Answer 3

非常感谢帮助我，我通过AnalyzeSkeleton获得了SekeletonResult使用IJ的响应结果。为此，我使用了IJ.run（imp，“Skeletonize”，“”）;

 // Initialize AnalyzeSkeleton_
  AnalyzeSkeleton_ skel = new AnalyzeSkeleton_();
 skel.calculateShortestPath = true;
 skel.setup("", imp);

 // Perform analysis in silent mode
 // (work on a copy of the ImagePlus if you don't want it displayed)
 // run(int pruneIndex, boolean pruneEnds, boolean shortPath, ImagePlus origIP, boolean silent, boolean verbose)
 SkeletonResult skelResult = skel.run(AnalyzeSkeleton_.NONE, false, true, null, true, false);

 // Read the results
 Object shortestPaths[] = skelResult.getShortestPathList().toArray();
 double branchLengths[] = skelResult.getAverageBranchLength();
 int branchNumbers[] = skelResult.getBranches();

 long totalLength = 0;
 for (int i = 0; i < branchNumbers.length; i++) {
     totalLength += branchNumbers[i] * branchLengths[i];
 }

 double cumulativeLengthOfShortestPaths = 0;
 for (int i = 0; i < shortestPaths.length; i++) {
     cumulativeLengthOfShortestPaths +=(Double)shortestPaths[i];
 }
  System.out.println("totalLength "+totalLength);
  System.out.println("cumulativeLengthOfShortestPaths "+cumulativeLengthOfShortestPaths);
System.out.println("getNumOfTrees "+skelResult.getNumOfTrees());
System.out.println("getAverageBranchLength "+skelResult.getAverageBranchLength().length);
System.out.println("getBranches "+skelResult.getBranches().length);
System.out.println("getEndPoints "+skelResult.getEndPoints().length);
System.out.println("getGraph "+skelResult.getGraph().length);
System.out.println("getJunctions "+skelResult.getJunctions().length);
System.out.println("getJunctionVoxels "+skelResult.getJunctionVoxels().length);
System.out.println("getListOfEndPoints "+skelResult.getListOfEndPoints().size());
System.out.println("getListOfJunctionVoxels "+skelResult.getListOfJunctionVoxels().size());
System.out.println("getMaximumBranchLength "+skelResult.getMaximumBranchLength().length);
System.out.println("getNumberOfVoxels "+skelResult.getNumberOfVoxels().length);
System.out.println("getQuadruples "+skelResult.getQuadruples().length); this method .but I am not able to find which method in Skeleton Result class returns bifuraction point could you please help me little more thanks Amar

分叉和脊终点

3 个答案: