Question

假设我有一个有年龄的列表（代表一个国家的预期寿命）：

ages= ['70.37668898', '72.15779044', '73.25278702', '72.18979793', '80.73137673','55.43124818' '54.16265064', '54.16540964', ...]

现在我的预期寿命范围增加了两倍（范围48-100），如下所示：

48-50,50-52, ...., 98-100

我想创建一个新列表，其中列出了每个年龄段的年龄段。如果给定年龄在预期寿命范围内，则内部列表包含1;如果不是，则内部列表包含0。

所以结果看起来像这样：

每个内部列表属于年龄

的年龄

[[0,0,0,0,1, ..., 0],[0,1,0,0,0, ..., 0],...]

我该如何做到这一点？

Answer 1

范围的结构有点模糊。让我们假设你的范围是这样的

ranges = [(48,50),(50,52),...(98,100)]

现在

ages= ['70.37668898', '72.15779044', '73.25278702', '72.18979793', '80.73137673','55.43124818' '54.16265064', '54.16540964', ...]

result = [ [ 1 if (r[0] <= age <= r[1]) else 0 for r in ranges] for age in ages]

或者如果您的范围是固定的，从50到100开始，增加2，您可以使用generator：

result = [ [ 1 if (r[0] <= age <= r[1]) else 0 for r in ( (i-2,i) for i in range(50,100,2)) ] for age in ages]

Answer 2

ages = [70.37668898, 72.15779044, 73.25278702, 72.18979793, 80.73137673, 55.43124818, 54.16265064, 54.16540964]
[[int(age >= 48+2*i and age <50+2*i) for i in range(25)] for age in ages]

结果

[[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]

这是（也许）你提出的问题。

包含范围的Python列表

2 个答案: