Question

我收到错误的线程错误，所以我想我需要从UI线程运行invalidate。通常我有类似的东西：

public void run() {

                runOnUiThread(new Runnable() {
}});

但我需要将此runnable命名为从方法引用它。我如何将runOnUiThread合并到这个中？

Handler viewHandler = new Handler();
Runnable updateView = new Runnable() {
@Override

public void run() {

    mEmulatorView.invalidate();

    if (statusBool == true) {
        for (int i = 1; i < dataReceived.length() - 1; i++) {

            if (dataReceived.charAt(i) == '>') {

                Log.d(TAG, "found >");
                deviceStatus = 0;
            }
            if (dataReceived.charAt(i) == '#'
                    && dataReceived.charAt(i - 1) != ')') {

                Log.d(TAG, "found #");
                deviceStatus = 1;
            }
            if ((i + 1) <= (dataReceived.length())
                    && dataReceived.charAt(i) == ')'
                    && dataReceived.charAt(i + 1) == '#') {

                Log.d(TAG, "found config )#");
                deviceStatus = 2;
            }

        }
        statusBool = false;
        viewHandler.postDelayed(updateView, 1000);

    }
}
};

称呼它：

public void onDataReceived(int id, byte[] data) {

        dataReceived = new String(data);
        ((MyBAIsWrapper) bis).renew(data);
        mSession.write(dataReceived);
        viewHandler.post(updateView);
}

Answer 1

您无需为其命名。如果您想发布自己，可以使用this关键字：

viewHandler.postDelayed(this, 1000);

<强>更新

由mSession.write(dataReceived);引起的错误的线程错误。 updateView不会导致任何问题。尝试将mSession.write包装为runnable并在ui线程上调用它。

Answer 2

让它工作，我只需要在UI线程中运行该写行，即使我认为它是？！

public void onDataReceived(int id, byte[] data) {

        dataReceived = new String(data);
        ((MyBAIsWrapper) bis).renew(data);

        runOnUiThread(new Runnable(){
            @Override
            public void run() { 
                mSession.write(dataReceived);       
            }});

        viewHandler.post(updateView);
    }

编辑代码以在UI线程上运行？

2 个答案: