获取和设置整数的高阶部分的有效或语法简单方法是什么?
答案 0 :(得分:26)
uint debugValue = 0xDEADBEEF;
// get
var toExtractHigh = debugValue >> 16;
Console.WriteLine("{0:X}", toExtractHigh);
// set
uint toSetHigh = 0xABAD;
debugValue = debugValue & 0x0000FFFF | toSetHigh << 16;
// this would work too:
// debugValue = debugValue & 0xFFFF | toSetHigh << 16;
Console.WriteLine("{0:X}", debugValue);
输出:
DEAD
ABADBEEF
C#非常支持共享相同内存位置的变量和位结构
来源:http://msdn.microsoft.com/en-us/library/acxa5b99(VS.80).aspx
using System;
using System.Runtime.InteropServices;
[StructLayout(LayoutKind.Explicit)]
struct TestUnion
{
[FieldOffset(0)]
public uint Number;
[FieldOffset(0)]
public ushort Low;
[FieldOffset(2)]
public ushort High;
}
class MainClass
{
public static void Main(string[] args)
{
var x = new TestUnion { Number = 0xABADF00D };
Console.WriteLine("{0:X} {1:X} {2:X}", x.Number, x.High, x.Low);
x.Low = 0xFACE;
Console.WriteLine("{0:X} {1:X} {2:X}", x.Number, x.High, x.Low);
x.High = 0xDEAD;
Console.WriteLine("{0:X} {1:X} {2:X}", x.Number, x.High, x.Low);
}
}
输出:
ABADF00D ABAD F00D
ABADFACE ABAD FACE
DEADFACE DEAD FACE
注意:由于C#没有像C中那样的宏功能,因此您可以使用联合方法加快速度。它比将变量传递给方法/扩展方法
更具性能或者,如果您想在C#中编码C,请使用unsafe
unsafe
{
uint value = 0xCAFEFEED;
// x86 is using low-endian.
// So low order array number gets the low order of the value
// And high order array number gets the high order of the value
Console.WriteLine(
"Get low order of {0:X}: {1:X}",
value, ((ushort *) &value)[0]);
Console.WriteLine(
"Get high order of {0:X}: {1:X}",
value, ((ushort*) &value)[1]);
((ushort*) &value)[1] = 0xABAD;
Console.WriteLine("Set high order to ABAD: {0:X}", value);
((ushort*) &value)[0] = 0xFACE;
Console.WriteLine("Set low order to FACE: {0:X}", value);
}
输出:
Get low order of CAFEFEED: FEED
Get high order of CAFEFEED: CAFE
Set high order to ABAD: ABADFEED
Set low order to FACE: ABADFACE
另一种unsafe
方法:
unsafe
{
uint value = 0xCAFEFEED;
Console.WriteLine(
"Get low order of {0:X}: {1:X}",
value, ((TestUnion*) &value)->Low);
Console.WriteLine(
"Get high order of {0:X}: {1:X}",
value, ((TestUnion*) &value)->High);
((TestUnion*) &value)->High = 0xABAD;
Console.WriteLine("Set high order to ABAD: {0:X}", value);
((TestUnion*) &value)->Low = 0xFACE;
Console.WriteLine("Set low order to FACE: {0:X}", value);
}
输出:
Get low order of CAFEFEED: FEED
Get high order of CAFEFEED: CAFE
Set high order to ABAD: ABADFEED
Set low order to FACE: ABADFACE
答案 1 :(得分:17)
与C / C ++相同:
// get the high order 16 bits
int high = 0x12345678 >> 16; // high = 0x1234
// set the high order 16 bits
high = (high & 0x0000FFFF) + (0x5678 << 16); // high = 0x56781234
编辑:因为我心情很好,所以你走了。请记住,不可变类型是不可变的! 'set'函数需要分配给某些东西。
public static class ExtensionMethods
{
public int LowWord(this int number)
{ return number & 0x0000FFFF; }
public int LowWord(this int number, int newValue)
{ return (number & 0xFFFF0000) + (newValue & 0x0000FFFF); }
public int HighWord(this int number)
{ return number & 0xFFFF0000; }
public int HighWord(this int number, int newValue)
{ return (number & 0x0000FFFF) + (newValue << 16); }
}
编辑2:第二个想法,如果你真的需要这样做而且不想在任何地方使用语法,请使用迈克尔的解决方案。给他+1给我一些新的东西。
答案 2 :(得分:4)
我想你想要Hiword / Hibyte或LoWord / Lobyte时不需要计算, 如果System.Int32从地址100开始(因此它占用地址100到103),你想要一个从地址100和101开始的两个字节作为LoWord,而Hiword是地址102和103.
这可以使用BitConverter类实现。这个类对这些位没有任何作用,它只使用地址来返回请求的值。
由于int / long等类型的大小因平台而异,WORD和DWORD有点混乱,我使用系统类型System.Int16 / Int32 / Int64。猜测System.Int32中的位数没有任何问题。
使用BitConverter,您可以将任何整数转换为从该位置开始的字节数组,并将适当长度的字节数组转换为相应的整数。不需要计算,也不会改变位,
假设您有一个System.Int32 X(以旧语言表示的DWORD)
LOWORD: System.Int16 y = BitConverter.ToInt16(BitConverter.GetBytes(x), 0);
HIWORD: System.Int16 y = BitConverter.ToInt16(BitConverter.GetBytes(x), 2);
好处是它适用于所有长度,你不必将像LOBYTE和HIORD这样的函数组合起来得到第三个字节:
HIByte(Hiword(x)) will be like: BitConverter.GetBytes(x)[3]
答案 3 :(得分:1)
另一种选择
public class Macro
{
public static short MAKEWORD(byte a, byte b)
{
return ((short)(((byte)(a & 0xff)) | ((short)((byte)(b & 0xff))) << 8));
}
public static byte LOBYTE(short a)
{
return ((byte)(a & 0xff));
}
public static byte HIBYTE(short a)
{
return ((byte)(a >> 8));
}
public static int MAKELONG(short a, short b)
{
return (((int)(a & 0xffff)) | (((int)(b & 0xffff)) << 16));
}
public static short HIWORD(int a)
{
return ((short)(a >> 16));
}
public static short LOWORD(int a)
{
return ((short)(a & 0xffff));
}
}
答案 4 :(得分:0)
我使用这两个功能...
public static int GetHighint(long intValue)
{
return Convert.ToInt32(intValue >> 32);
}
public static int GetLowint(long intValue)
{
long tmp = intValue << 32;
return Convert.ToInt32(tmp >> 32);
}