在Scala的immutable.Queue
中,有两种名为enqueue
的方法:
/** Creates a new queue with element added at the end
* of the old queue.
*
* @param elem the element to insert
*/
def enqueue[B >: A](elem: B) = new Queue(elem :: in, out)
/** Returns a new queue with all elements provided by an `Iterable` object
* added at the end of the queue.
*
* The elements are prepended in the order they are given out by the
* iterator.
*
* @param iter an iterable object
*/
def enqueue[B >: A](iter: Iterable[B]) =
new Queue(iter.toList reverse_::: in, out)
我不知道如何解决歧义,并打电话给第二个。这是我尝试过的:
Welcome to Scala version 2.10.0 (Java HotSpot(TM) 64-Bit Server VM, Java 1.7.0_07).
Type in expressions to have them evaluated.
Type :help for more information.
scala> import collection.immutable.Queue
import collection.immutable.Queue
scala> val q: Queue[Int] = Queue(1,2,3)
q: scala.collection.immutable.Queue[Int] = Queue(1, 2, 3)
scala> q.enqueue(Iterable(4))
res0: scala.collection.immutable.Queue[Any] = Queue(1, 2, 3, List(4))
scala> q.enqueue[Int](Iterable(4))
<console>:10: error: overloaded method value enqueue with alternatives:
(iter: scala.collection.immutable.Iterable[Int])scala.collection.immutable.Queue[Int] <and>
(elem: Int)scala.collection.immutable.Queue[Int]
cannot be applied to (Iterable[Int])
q.enqueue[Int](Iterable(4))
^
答案 0 :(得分:8)
棘手,棘手!
我created a ticket关于它。你看,你被类型误导了!
scala> q.enqueue(scala.collection.Iterable(4))
res8: scala.collection.immutable.Queue[Any] = Queue(1, 2, 3, List(4))
scala> q.enqueue(scala.collection.immutable.Iterable(4))
res9: scala.collection.immutable.Queue[Int] = Queue(1, 2, 3, 4)
默认情况下导入的Iterable
是scala.collection.Iterable
,可以是可变的也可以是不可变的,但不可变队列需要不可变 Iterable
。< / p>
答案 1 :(得分:0)
Scala 2.13 弃用重载而支持 enqueueAll
。
同时,一种更简单的绕过方法是明确提及类型。
val q = Queue[Vector[Int]]()
val uQ: Queue[Vector[Int]] = q.enqueue(Vector(6))