Question

对于初学者来说，这是一个简单的tic tac toe版本，我正在创建一个设计困难的AI，我的代码中有AI（随机）的部分代码。忽略该功能，但我的主要困难是正确地在板上打印移动。出于某种原因，每当我选择是否想要成为X或O时，它会自动将我提交到X.此外，如果我选择除位置A以外的任何内容，它将在位置A上打印X.我想，如果有人愿意帮我告诉我，我的编码在哪里出错了。另外，为了让我的游戏更加清晰和简单，我想在移动后并排打印Board和Board 2。这将显示可用的移动，因此如果移动A和B，它们将不会显示在船上。如果有人可以教我如何做并排印刷，这将是伟大的。

print "**********************"
print "*THE GAME WILL BEGIN.*"
print "**********************"
import random
indx=0
move_storage=[]
move=["","","","","","","","",""]
#**************************************************
#            This is the original board           *
#**************************************************
def board():
    print "This is the tictactoe board we will be playing on"
    print "         |         |        "
    print "    A    |    B    |    C   "
    print "         |         |        "
    print "------------------------------"
    print "         |         |        "
    print "    D    |    E    |    F   "
    print "         |         |        "
    print "------------------------------"
    print "         |         |        "
    print "    G    |    H    |    I   "
    print "         |         |        "
board()
#****************************************************
#This is the board where the moves will be displayed*
#****************************************************
def board2(move):
    print "  ",move[0],"  |   ",move[1],"     |     ",move[2],"     "
    print "       |          |     "
    print " -----------------------  "
    print "       |          |     "
    print "  ",move[3],"   |    ",move[4],"    |     ",move[5],"     "
    print "       |          |     "
    print " -----------------------  "
    print "       |          |     "
    print "  ",move[6],"   |     ",move[7],"   |    ",move[8],"     "

#This function will store all of the moves inputed.
def movestorage(move_storage, move):
    move_storage= move_storage + [move]
#This function will randomize the computer's move
def computer_move():
    move_random=random.randint(1,9)
    move[move_random]=computer_choice
    movestorage(move_storage, move)
player=raw_input("Would you like to play as x or o-->")
player_order=raw_input("Would you like to go first,y/n?-->")
while indx==0:
    if 'x' or 'X' == player:
        player_choice="X"
        computer_choice="O"
        if 'y' or 'Y' in player_order:
            print 
        elif 'n' or 'N' in player_order:
            print
            print "The computer will go first, press ENTER to see the computers turn"
    elif 'o' or 'O' == player:
        player_choice="O"
        computer_choice="X"
        if 'y' or 'Y' in player_order:
            print
        elif 'n' or 'N' in player_order:
            print
            print "The computer will go first, press ENTER to see the computers turn"
    x=0
    while 2>x:  #This is where the player decides where he wants to go
        choice=raw_input("Choose where you would like to move-->")
        if choice == 'a' or 'A':
            move[0]=player_choice
            movestorage(move_storage, move)
        elif choice == 'b' or 'B':
            move[1]=player_choice
            movestorage(move_storage, move)
        elif choice == 'c' or 'C':
            move[2]=player_choice
            movestorage(move_storage, move)
        elif choice == 'd' or 'D':
            move[3]=player_choice
            movestorage(move_storage, move)
        elif choice == 'e' or 'E':
            move[4]=player_choice
            movestorage(move_storage, move)
        elif choice == 'f' or 'F':
            move[5]=player_choice
            movestorage(move_storage, move)
        elif choice == 'g' or 'G':
            move[6]=player_choice
            movestorage(move_storage, move)
        elif choice == 'h' or 'H':
            move[7]=player_choice
            movestorage(move_storage, move)
        elif choice == 'i' or 'I':
            move[8]=player_choice
            movestorage(move_storage, move)
        board2(move)

我也有一些空白的打印声明，但它们不是错误。

Answer 1

if 'x' or 'X' == player 不意味着player是x还是X，而是if ('x') or ('X' == player)，所以请测试{{} {1}}作为布尔值，并将'x'测试为布尔值，如果第一个或第二个部分为'X' == player，则整个表达式为True。

由于第一个字符串的长度大于0，因此总是为True，并且永远不会进行第二次测试：

True

使用：

>>> bool('x' or 'X' == 'fiddlesticksandflapdoodles')
True
>>> bool('x')
True
>>> bool('X' == 'fiddlesticksandflapdoodles')
False

代替，或者：

if 'x' == player or 'X' == player:

或：

if player in ('x', 'X'):

所有这些测试同样的事情。

这适用于针对大写和小写字母测试的所有if player.lower() == 'x':语句，例如if和'n' or 'N'。

至于你的'o' or 'O'测试的长列表;只需使用映射将字母映射到数字：

if choice

现在您可以使用choices = {letter: number for number, letter in enumerate('abcdefghi')}映射到索引：

choices

python中的tictactoe（打印动作有问题）

1 个答案: