使用T-SQL,我正在尝试找到让"Test One"
成为"One, Test"
的最简单方法。
如果列中只有2个单词,并且它们之间有空格,则基本上切换“”和“,”。
例如:
Before After
Test One One, Test
Test Two One Test Two One
Test, Three Test, Three
答案 0 :(得分:6)
这个怎么样:
select col Before,
case
when col like '%,%' then col
when len(replace(col, ' ', '')) = len(col) -1
then reverse(substring(reverse(col), 1, charindex(' ', reverse(col))-1))+', '+substring(col, 1, charindex(' ', col)-1)
else col
end After
from yourtable
见SQL Fiddle with Demo。结果是:
| BEFORE | AFTER |
-------------------------------
| Test One | One, Test |
| Test Two One | Test Two One |
| Test, Three | Test, Three |
答案 1 :(得分:2)
<强> SQL Fiddle 强>
DECLARE @Tests TABLE (
Before VARCHAR(50)
)
INSERT INTO @Tests Values ('Test One')
INSERT INTO @Tests Values ('Test Two One')
INSERT INTO @Tests Values ('Test, Three')
SELECT
Before,
CASE
WHEN
-- If there is no comma...
CHARINDEX(',', Before) = 0
-- And if there is only one space...
AND CHARINDEX(' ', RIGHT(Before, LEN(Before) -
CHARINDEX(' ', Before))) = 0
THEN
-- Then perform the swap.
RIGHT(Before, LEN(Before) - CHARINDEX(' ', Before)) + ', '
+ LEFT(Before, CHARINDEX(' ', Before))
-- Otherwise, retain the "before" value.
ELSE Before
END AS After
FROM @Tests
答案 2 :(得分:0)
这是我的看法:不是最好的,因为它使用了很多字符串函数......
假设:
你只有两个字;)
有一个空格/或其他角色......
代码:
SELECT CHARINDEX(' ',name) splitposition,
SUBSTRING(name, 1, CHARINDEX(' ',name)-1) firstword,
SUBSTRING(name, CHARINDEX(' ',name), len(name)) lastword,
(SUBSTRING(name, CHARINDEX(' ',name), len(name)) +
', ' + SUBSTRING(name, 1, CHARINDEX(' ',name)-1)) as swapped
from moneys;
结果:
| SPLITPOSITION | FIRSTWORD | LASTWORD | SWAPPED |
----------------------------------------------------
| 5 | test | one | one, test |
ps:我在sql server中使用旧表进行演示..