Question

嘿伙计们我试图在我的postgres db中运行此查询，但它返回错误：[Err]错误：语法错误在或附近“，” 第13行：而不是substr（a.zoneiddest，1,3）= any（'254'，'255'，'256'......

查询就像这样

SELECT
    to_char(a.CALLDATE, 'yyyymm') AS month,
    min(a.calldate) AS start_time,
    max(a.calldate) AS end_time,
    ceil(SUM(a.CALLDURATION::INT) / 60) AS minutes,
    COUNT(DISTINCT a.IDENTIFIANT) AS distinct_callers,
    a.zoneiddest AS country_code,
    b.country
FROM cdr_data a,
    country_codes b
WHERE a.CALLSUBCLASS = '002'
  AND a.CALLCLASS = '008'
  AND a.zoneiddest::INT > 0
  AND SUBSTR(a.CALLEDNUMBER, 1, 2) NOT IN
    ( '77', '78', '75', '70', '71', '41', '31', '39', '76', '79' )
  AND NOT substr(a.zoneiddest, 1, 3) = ANY
    ( '254', '255','256', '211', '257', '250', '256' )
  AND trim(a.zoneiddest) = trim(b.country_code)
GROUP BY
    to_char(a.CALLDATE, 'yyyymm'),
    a.zoneiddest,
    b.country
ORDER BY 1

同样的查询在oracle中运行良好，只需对a.zoneiddest :: integer＆gt;进行一些小的改动。 0到a.zoneiddest＆gt; 0

我可能做错了什么

Answer 1

问题在于您的ANY运营商。如果我正确理解您的查询，您只需将其替换为NOT IN语句即可。

SELECT to_char (a.CALLDATE,'yyyymm') as month,min(a.calldate) as 
start_time,max(a.calldate) as end_time,
ceil(SUM (a.CALLDURATION::integer) / 60) AS minutes,
COUNT (DISTINCT a.IDENTIFIANT) AS distinct_callers,
a.zoneiddest as country_code,b.country
FROM cdr_data a,COUNTRY_CODES b
WHERE  a.CALLSUBCLASS = '002'
AND  a.CALLCLASS = '008'
and a.zoneiddest::integer > 0
AND SUBSTR (a.CALLEDNUMBER, 1, 2) NOT IN
  ('77', '78', '75', '70', '71', '41', '31', '39', '76','79')
// This line
AND substr(a.zoneiddest , 1 ,3) NOT IN
  ('254','255','256','211','257','250','256')
// End of line
and trim(a.zoneiddest)  = trim(b.country_code)
GROUP BY to_char (a.CALLDATE,'yyyymm') ,a.zoneiddest,b.country
ORDER BY 1

Answer 2

尝试使用关键字any与参数数组合如下：

= any (ARRAY['254','255','256','211','257','250','256'])

我的SQL查询出错

2 个答案: