Question

目录递归遍历不超过2个级别。为什么会这样？

=============================================================


    currentFolderDir = '.'; % pwd
    % path('C:\Users\EI\Documents\MATLAB\OO\Simple Object Creation in Object Oriented');

    depthLevel = 0;
    folderCount = 0;
    fileCount = 0;

    fprintf('=====================================\n');  
    fprintf('Depth level: %d\n', depthLevel); 
    [folderCount, fileCount] = fileDirectoryRecursiveTraversal (currentFolderDir, depthLevel, folderCount, fileCount);

=============================================================




    function [folderCount, fileCount] = fileDirectoryRecursiveTraversal (currentFile, depthLevel, folderCount, fileCount)    

        for i = 1:depthLevel
            fprintf('\t\t');
        end

        fprintf('%s\n', currentFile ); % Print the name of the entry  
        %isdir(currentFile)  % [ERR] can't go beyond level 2
        %pause;

        if (isdir(currentFile)) % Check if it is a directory   
            folderCount = folderCount + 1;
            fprintf('\nThere are %d folders.\n', folderCount);
            pause

            depthLevel = depthLevel + 1;
            fprintf('=====================================\n');  
            fprintf('Depth level: %d\n', depthLevel); 

             % Get a list of all the entries in the directory
             entries = dir(currentFile);

             % entries(1).name = '.'
             % entries(2).name = '..'
             numberOfEntries = length(entries); % including current folder and pointer to folder 1 level up


             % Ensure that the list is not null
             % if( (numberOfEntries - 2) ~= 0 ) % 2: % entries(1).name = '.'; % entries(2).name = '..'
             if(numberOfEntries ~= 2) 
                % Loop over all the entries
                for i = 3:numberOfEntries    
                   % Recursive call to traverse
                   [folderCount, fileCount] = fileDirectoryRecursiveTraversal( entries(i).name, depthLevel, folderCount, fileCount); % i = 3:numberOfEntries   
                end

                fprintf('\nDepth level: %d\n', depthLevel); 
                fprintf('There are %d files.\n\n', fileCount);  
                fileCount = 0;
             else
                % disp('cccccccccccccccccccc')
                fileCount = 0; % empty folder
             end
        else
           fileCount = fileCount + 1; 
           folderCount = 0;
        end    


        folderCount = folderCount - 1;
        depthLevel = depthLevel - 1; % exit level    
    end

Answer 1

我已经使用了一个函数来递归处理某个目录中的文件。它正确地遍历所有子目录并显示文件名，但它不显示depthlevel，folderCount和fileCount。它应该很容易适应，但如果你需要帮助，请告诉我：

function processDirectory(path)

if ~strcmp(path(end), filesep)
    path(end+1)=filesep;
end
dirInfo= dir(path);
files=~[dirInfo.isdir];
fileNames={dirInfo(files).name};
disp(path);
if ~isempty(fileNames)
    for i=1:length(fileNames)
        % Do whathever (show file names?)
        disp(fileNames(i));
    end
end

% For each subdir, call itself again
isDir=[dirInfo.isdir];
dirNames={dirInfo(isDir).name};
dirNames(strcmp(dirNames, '.') | strcmp(dirNames, '..'))=[];

for i=1:length(dirNames)
    processDirectory([path dirNames{i} filesep]);    
end

目录递归遍历在Matlab中不超过2个级别

1 个答案: