Question

我有以下SQL代码：

DELIMITER $$

CREATE FUNCTION flighttime (p_arrival(DATE), p_departure(DATE))
RETURNS CHAR(50)
BEGIN
    DECLARE v_hour INT;
    DECLARE v_minute INT;
    DECLARE v_htext CHAR(10);
    DECLARE v_mtext CHAR(10);
    DECLARE v_flighttime CHAR(50);
    DATEDIFF(minute, p_departure, p_arrival) AS v_minute;
    v_hour = v_minute/60;
    v_minute = v_minute-(v_hour*60);

    IF v_hour<2 AND v_minute<2 THEN SET v_htext=' hour and ' AND v_mtext=' minute';
    ELSEIF v_hour<2 AND v_minute>1 THEN SET v_htext=' hour and ' AND v_mtext=' minutes';
    ELSEIF v_hour>1 AND v_minute<2 THEN SET v_htext=' hours and ' AND v_mtext=' minute';
    ELSE SET v_htext=' hours and ' AND v_mtext=' minutes';

    SET v_flighttime = CONCAT(v_hour, v_mtext, v_minute, v_mtext);
    RETURN v_flighttime;
END

$$
DELIMITER;

校正：

DELIMITER $$
CREATE FUNCTION flighttime (p_arrival DATETIME, p_departure DATETIME)
    RETURNS CHAR(70)
BEGIN
    DECLARE v_hour INT;
    DECLARE v_minute INT;
    DECLARE v_htext CHAR(15);
    DECLARE v_mtext CHAR(15);
    DECLARE v_flighttime CHAR(70);
    SET v_hour = HOUR(TIMEDIFF(p_departure, p_arrival));
    SET v_minute = MINUTE(TIMEDIFF(p_departure, p_arrival));
    IF v_hour<2 AND v_minute<2 THEN 
        SET v_htext = ' hour and ';
        SET v_mtext=' minute';
    ELSEIF v_hour<2 AND v_minute>1 THEN 
        SET v_htext=' hour and '; 
        SET v_mtext=' minutes';
    ELSEIF v_hour>1 AND v_minute<2 THEN 
        SET v_htext=' hours and ';
        SET v_mtext=' minute';
    ELSE 
        SET v_htext=' hours and ';
        SET v_mtext=' minutes';
    END IF;

    SET v_flighttime = CONCAT(v_hour, v_htext, v_minute, v_mtext);

    RETURN v_flighttime;
END $$
DELIMITER ;

但是我在phpMyAdmin 3.5.2.2中得到了错误消息：

1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(DATE), p_departure(DATE)) RETURNS CHAR(50) BEGIN DECLARE v_hour INT; DECLAR' at line 1

之前我有1064个错误，并且大多能够通过使用后退滴答或正常抽搐来解决它们。不幸的是，这次它没有帮助。

此功能的目标是计算两个日期之间的差异，并以小时和分钟为单位给出差异。也是为了区分单数和复数。

如果有人为我提供解决方案或线索如何解决这个问题，我将不胜感激。

感谢您的帮助。它现在解决了（我还要将DATE更改为DATETIME :)）

Answer 1

您的申报无效。它应该是

CREATE FUNCTION flighttime (p_arrival DATE, p_departure DATE)
....

然后由于值设置无效，其他错误会很快上升，您应该使用SET

SET v_minute = DATEDIFF(minute, p_departure, p_arrival);
SET v_hour = v_minute/60;
SET v_minute = v_minute-(v_hour*60);

完整代码，

DELIMITER $$
CREATE FUNCTION flighttime (p_arrival DATE, p_departure DATE)
RETURNS CHAR(50)
BEGIN
    DECLARE v_hour INT;
    DECLARE v_minute INT;
    DECLARE v_htext CHAR(10);
    DECLARE v_mtext CHAR(10);
    DECLARE v_flighttime CHAR(50);
    SET v_minute = DATEDIFF(minute, p_departure, p_arrival);
    SET v_hour = v_minute/60;
    SET v_minute = v_minute-(v_hour*60);

    IF v_hour<2 AND v_minute<2 THEN 
        SET v_htext = ' hour and ';
        SET v_mtext=' minute';
    ELSEIF v_hour<2 AND v_minute>1 THEN 
        SET v_htext=' hour and '; 
        SET v_mtext=' minutes';
    ELSEIF v_hour>1 AND v_minute<2 THEN 
        SET v_htext=' hours and ';
        SET v_mtext=' minute';
    ELSE 
        SET v_htext=' hours and ';
        SET v_mtext=' minutes';
    END IF;

    SET v_flighttime = CONCAT(v_hour, v_mtext, v_minute, v_mtext);

    RETURN v_flighttime;
END $$
DELIMITER ;

存储功能 - 错误＃1064 - Backtick / Tick？

1 个答案: