我正在处理一些代码,并且遇到了这个存储过程问题...现在花了很长时间看着它,所以如果有人能告诉我这是一个菜鸟的话,那就请。
我收到以下错误:
错误代码:1064 您的SQL语法有错误;检查与您的MySQL服务器版本对应的手册,以便在'@ownerid varchar(50)附近使用正确的语法; 声明@active tinyint; 声明@subuser tinyint; 设置'第4行
关于此代码:
DELIMITER //
USE `test`//
DROP PROCEDURE IF EXISTS `getAccount`//
CREATE DEFINER=`peter`@`%` PROCEDURE `getAccount`( IN cid VARCHAR(20))
BEGIN
DECLARE cardid VARCHAR(50);
DECLARE @ownerid VARCHAR(50);
DECLARE @active TINYINT;
DECLARE @subuser TINYINT;
SET cardid = MD5( cid + SHA1(cid + 'a salt value'));
SELECT @active = active, @ownerid = ownerid, @subuser = subuser FROM cards_tbl WHERE cardhash = cardid;
IF @active = 1 THEN
IF @subuser = 1 THEN
SELECT subuser_m2s_tbl.name,subuser_m2s_tbl.image, user_saldo.saldo AS credits FROM subuser_m2s_tbl
JOIN user_saldo ON subuser_m2s_tbl.subhash = user_saldo.userhash
WHERE subuser_m2s_tbl.subhash = @ownerid;
ELSE
SELECT user_m2s_tbl.name,user_m2s_tbl.image, user_saldo.saldo AS credits FROM user_m2s_tbl
JOIN user_saldo ON user_m2s_tbl.userhash = user_saldo.userhash
WHERE user_m2s_tbl.userhash = @ownerid;
END IF;
END IF;
END$$
DELIMITER ;
是存储过程的新手,所以它非常简单..... 提前致谢
答案 0 :(得分:1)
你应该使用':='而不是' ='当你想在SELECT语句中将值传递给变量时,否则MySQL只会与操作数进行比较。
SELECT
active_var := active, ownerid_var := ownerid, subuser_var := subuser
FROM
cards_tbl
WHERE
cardhash = cardid;
您也可以使用SELECT INTO语句,例如 -
SELECT
active, ownerid, subuser
INTO
active_var, ownerid_var, subuser_var
FROM
cards_tbl
WHERE
cardhash = cardid;
答案 1 :(得分:0)
可能是失踪的@
DECLARE cardid VARCHAR(50);
...
DECLARE @cardid VARCHAR(50);