将php / mysql列输出显示为行

时间:2013-01-11 11:15:03

标签: php mysql

我有以下语法用于在PHP中显示MySQL查询:

 function get_dayssincecapture($db)  
  {    
    $result = $db->query("SELECT DATEDIFF(now(), sarrive)as days,count(loadnumber) as loads from v2loads where  adminstatus='captured' group by DATEDIFF(now(), sarrive) "); 
    return $result; 
  } 
  $dayssincecapture = get_dayssincecapture($db); 

显示语法:

<table border=1>
    <tr>
    <? while($row = $dayssincecapture->fetch(PDO::FETCH_ASSOC)) { ?>
    <td><? echo $row['days']; ?><br><? echo $row['loads']; ?></td>
    <? } ?>
    </tr>
</table>

这会产生以下屏幕输出

enter image description here

如何通过表格语法更改以将days字段作为行标题并将load字段作为表格的第二行?

所以我想要的是:

enter image description here

一如既往地谢谢,

3 个答案:

答案 0 :(得分:4)

尝试:

<?php
$dayssincecapture = get_dayssincecapture($db); 
$data = array('days' => array(), 'loads' => array());

while($row = $dayssincecapture->fetch(PDO::FETCH_ASSOC)) {
    $data['days'][]  = $row['days'];
    $data['loads'][] = $row['loads'];
}
?>

<table style="border: 1px solid #000">
    <tr>
        <td>Days</td>
        <?php foreach ( $data['days'] as $day ) { ?>
            <td><?php echo $day; ?></td>
        <?php } ?>
    </tr>
    <tr>
        <td>Loads</td>
        <?php foreach ( $data['loads'] as $load ) { ?>
            <td><?php echo $load; ?></td>
        <?php } ?>
    </tr>
</table>

答案 1 :(得分:1)

如果您想在MySQL中执行此类转换,那么您将转动数据。 MySQL没有pivot函数,但您可以使用带有CASE语句的聚合函数来复制它:

select 
  count(case when DATEDIFF(now(), sarrive) = 1 then loadnumber end) as Day_1,
  count(case when DATEDIFF(now(), sarrive) = 2 then loadnumber end) as Day_2,
  count(case when DATEDIFF(now(), sarrive) = 3 then loadnumber end) as Day_3,
  count(case when DATEDIFF(now(), sarrive) = 4 then loadnumber end) as Day_4,
  count(case when DATEDIFF(now(), sarrive) = 5 then loadnumber end) as Day_5,
  count(case when DATEDIFF(now(), sarrive) = 6 then loadnumber end) as Day_6,
  count(case when DATEDIFF(now(), sarrive) = 7 then loadnumber end) as Day_7
from v2loads
where adminstatus='captured' 

您也可以在预准备语句中编写此代码,以便动态创建此代码,因为这些值将是未知的。

答案 2 :(得分:1)

您可以尝试:

<?php

while($row = $dayssincecapture->fetch(PDO::FETCH_ASSOC)) {
    $days_row .= "<td>" . $row['days'] . "</td>";
    $loads_row .= "<td>" . $row['loads'] . "</td>";
}

?>
<table> 

  <tr>
    <td>Days</td>
    <?php echo $days_row; ?>
  </tr>
  <tr>
    <td>Loads</td>
    <?php echo $loads_row; ?>
  </tr>
</table>