Question

这是antivirus_detail表：

+-----------------------------+--------------+------+-----+---------+-----------

| Field                       | Type         | Null | Key | Default | Extra
|
+-----------------------------+--------------+------+-----+---------+-----------

| Emp_id                      | int(11)      | YES  | MUL | NULL    |

| Computer_id                 | int(11)      | YES  | MUL | NULL    |

| Antivirus_id                | int(11)      | NO   | PRI | NULL    |auto_incre
                                                                          ment 
| Antivirus_name              | varchar(50)  | YES  |     | NULL    |

| Antivirus_key               | varchar(50)  | YES  |     | NULL    |

| Antivirus_installation_date | date         | YES  |     | NULL    |

| Antivirus_expiration_date   | date         | YES  |     | NULL    |

这是hardware_description表：

+------------------+--------------+------+-----+---------+----------------+
| Field            | Type         | Null | Key | Default | Extra          |
+------------------+--------------+------+-----+---------+----------------+
| Computer_id      | int(11)      | NO   | PRI | NULL    | auto_increment |
| Emp_id           | int(11)      | NO   | MUL | NULL    |                |
| PC_type          | varchar(20)  | YES  |     | NULL    |                |
| Operating_system | varchar(20)  | YES  |     | NULL    |                |
| Product_key      | varchar(30)  | YES  |     | NULL    |                |
| Assign_date      | date         | YES  |     | NULL    |                |

Emp_id是来自不同员工表和这两个表的外键。 Computer_id是hardware_description表中防病毒表中的外键。

这是我的PHP代码：

<?php require_once 'includes/dbconnection.php'; ?>
<?php require_once 'includes/functions.php'; ?>

<?php
    $id="1";

    $sql ="SELECT b.*, c.* FROM hardware_description b, antivirus_detail c WHERE b.Computer_id = c.Computer_id AND c.Emp_id = '$id'";

    $result = mysqli_query($connection, $sql);
    //var_dump($result);

?>

    <table cellpadding="5" border="0">
        <tr>
            <th style="text-align: left;">Employee ID</th>
            <th style="text-align: left;">Computer ID</th>
            <th style="text-align: left;">Operating System</th>
            <th style="text-align: left;">PC Type</th>
            <th style="text-align: left;">Antivirus ID</th>

        </tr>
    <?php while($row = mysqli_fetch_array($result)) { ?>
        <tr>
            <td><?php echo $row['Emp_id']; ?></td>
            <td><?php echo $row['Computer_id']; ?></td>
            <td><?php echo $row['Operating_system']; ?></td>
            <td><?php echo $row['PC_type']; ?></td>
            <td><?php echo $row['Antivirus_id']; ?></td>

        </tr>
    <?php
    } 
    ?>
    </table>

现在，显示：

Employee ID Computer ID Operating System PC Type Antivirus ID 
1            2           Windows XP      Desktop    1          
1            2           Windows XP      Desktop    2

我希望输出如下：

Employee ID Computer ID Operating System PC Type   Antivirus ID
1              2          Windows XP     Desktop   1,2

我希望所有攻击计算机ID的防病毒ID都显示为数组。我如何实现这一目标？

Answer 1

在您的查询中，您必须使用GROUP_CONCAT来连接Antivirus_ids。

将您的SQL查询更改为类似的内容;

$sql ="SELECT b.Emp_id, b.Computer_id, b.Operating_system, b.PC_type, GROUP_CONCAT(c.Antivirus_id SEPARATOR ', ') as concatenated_ids FROM hardware_description b, antivirus_detail c WHERE b.Computer_id = c.Computer_id AND c.Emp_id = '$id' GROUP BY c.Antivirus_id";

在获取数据时，请将此$row['Antivirus_id'];更改为$row['concatenated_ids'];。

PHP：将一列显示为数组字段

1 个答案: