将一组电子邮件地址和数字放在一起,使用join在sql中从数据库中取出。
SELECT ost_ticket.email, ost_ticket_response.time_taken
FROM ost_ticket
INNER JOIN ost_ticket_response
ON ost_ticket_response.ticket_id=ost_ticket.ticket_id
WHERE time_taken > 0
输出
('log@tome.ie', 100)
('log@tome.ie', 100)
('log@tome.ie', 10)
('log@tome.ie', 2)
('temp@eircom.net', 30L)
('john@tome-ireland.com', 20L)
('1234567@tome.ie', 1234567L)
('log@tome.ie', 2L)
('log@tome.ie', 2L)
('valerie@tome.ie', 30L)
('john@cmi-tome.com', 10L)
('john@cmi-tome.com', 40L)
希望能够获取所有电子邮件地址并且总计如此
log@tome.ie = 216
temp@eircom.net = 30
john@tome-ireland.com = 70
1234567@tome.ie = 1234567
john@cmi-tome.com = 50
是否可以通过sql或输出后在python中完成?
答案 0 :(得分:3)
从数据库中提取数据时,请使用如下查询:
select emailaddress, sum(number) as total
from t
group by emailaddress