mysql：转身就好

Question

我有一张这样的表

id, title
1, hello world
2, world hello

并且我想搜索与此php表达式匹配的所有ID：

$searchstring = "hello world is yours"
if (strstr($searchstring,mysql(title)){echo found}

在mysql中我经常使用它：

select id from table where title LIKE '%....%'

但我需要另一面：

select id from table where "hello word is yours" LIKE %title%

结果必须是id 1“hello word”

任何人都可以告诉我正确的语法吗？

Answer 1

select id from table
where 'hello word is yours' LIKE concat('%', replace(title, ' ', '%'), '%')

Answer 2

使用CONCAT

select id 
from tableName
where 'hello word is yours' LIKE CONCAT('%',title,'%')

Answer 3

作为替代方案，您可以考虑使用Full Text Search。如果您创建FTS索引，它可以更有效，并提供直观的搜索字符串：

SELECT id FROM tablename WHERE MATCH (title)
      AGAINST ('hello world is yours' IN BOOLEAN MODE);