我有这样的单桌:
UserID user_properties_key user_properties_value(String)
User1 email user_email@gmail.com
weight 55
我希望得到这样的结果:
UserId email weight
User1 user_email@gmail.com 55
User2 user2_email@email.com 155
我当前的查询显示:
SELECT
T1.UserId as UserId,
T1.user_properties_value AS email,
T2.user_properties_value AS weight,
FROM (FLATTEN([database20160814], user_properties_key )) AS T1
JOIN
(FLATTEN([database20160814], user_properties_key )) AS T2
ON
T1.userId = T2.userId
WHERE
T1.user_properties_key="email"
AND T2.user_properties_key="weight"
GROUP BY
V0,
V1,
V2
如果我想要获取更多字段,查询不起作用或需要很长时间
答案 0 :(得分:1)
尝试以下
def backward_list(n):
numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
if n == 0 or n == 1:
x = numbers.index(n)
else:
x = (numbers.index(n)-10)
return [numbers[x-2],numbers[x-1],numbers[x],numbers[x+1],numbers[x+2]]
OR
In [1]: for i in range(10):
.....: print backward_list(i)
.....:
[8, 9, 0, 1, 2]
[9, 0, 1, 2, 3]
[0, 1, 2, 3, 4]
[1, 2, 3, 4, 5]
[2, 3, 4, 5, 6]
[3, 4, 5, 6, 7]
[4, 5, 6, 7, 8]
[5, 6, 7, 8, 9]
[6, 7, 8, 9, 0]
[7, 8, 9, 0, 1]
您的问题并不清楚,所以我假设您的表格如下
答案 1 :(得分:0)
这通常称为数据透视表操作。之前的问题和答案举例说明:How to simulate a pivot table with BigQuery?
如果您使用standard SQL,则需要更改示例中的某些函数和语法,但原理是相同的。