public static enum pie {
APPLE_PIE1(1, 250),
PUMPKIN_PIE1(2, 300),
OTHER_PIE1(3, 350),
APPLE_PIE2(4, 400),
OTHER_PIE2(5, 450),
PUMPKIN_PIE2(6, 500),
APPLE_PIE3(7, 550),
;
private static Map<Integer, pie> pie = new HashMap<Integer, pie>();
static {
for(pie pie : pie.values()) {
pie.put(pie.getId(), pie);
}
}
public static pie forId(int id) {
return pie.get(id);
}
private pie(int id, double exp) {
this.id = id;
this.exp = exp;
}
public int id;
public double exp;
System.out.println("My favorite type of pie is " + pie.toString().toLowerCase().replaceAll("_", " ").replaceAll("2", "").replaceAll("3", "").replaceAll("4", "") + ".");
示例代码被撕掉了,但我怎么做'.replaceAll(“ number ”,“”)'用更简单的代码替换所有小于或等于4的数字?创建一个新的.replaceAll 3次是多余的。如果我......:
double number[] = {1, 2, 3, 4};
pie.toString().toLowerCase().replaceAll("_", " ").replaceAll(number.toString(), "") + ".");
......我会收到一个令人讨厌的错误。
这是错误......
SEVERE: An error occurred in an executor service! The server will be halted immediately.
java.util.regex.PatternSyntaxException: Unclosed character class near index 9
[D@12452e8
^
at java.util.regex.Pattern.error(Unknown Source)
at java.util.regex.Pattern.clazz(Unknown Source)
at java.util.regex.Pattern.sequence(Unknown Source)
at java.util.regex.Pattern.expr(Unknown Source)
at java.util.regex.Pattern.compile(Unknown Source)
at java.util.regex.Pattern.<init>(Unknown Source)
at java.util.regex.Pattern.compile(Unknown Source)
at java.lang.String.replaceAll(Unknown Source)
答案 0 :(得分:0)
要修复错误,您应该更换
double number[] = {1, 2, 3, 4};
通过
String number = "[1, 2, 3, 4]";
但我不会使用replaceAll来做到这一点。相反,我会以与其他字段类似的方式向您的枚举添加label
字段,并调用getLabel()
而不是toString()
,或覆盖toString()
以返回标签:
public static enum pie {
APPLE_PIE1(1, 250, "apple pie"),
PUMPKIN_PIE1(2, 300, "pumpkin pie"),
...
private int id;
private double exp;
private String label;
private pie(int id, double exp, String label) {
this.id = id;
this.exp = exp;
this.label = label;
}
public String getLabel() {
return label;
}
// optional: I wouldn't do it as it would make debugging harder
@Override
public String toString() {
return label;
}
}