Question

我在Android中有一种调用Web服务的方法，如下所述。

现在，当我的类调用此方法时，我无法看到任何异常，只能在System.out.println("entered into call service method 2");日志之前。我可以在logcat看到状态response = httpclient.execute(httppost);不起作用，System.out.println("entered into call service method 3");没有在logcat上显示任何异常。知道为什么会这样吗？如何解决？

           public void callService() throws Exception {
        System.out.println("entered into call service method");
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://localhost:81/a.php");
        HttpResponse response;
        System.out.println("entered into call service method 1");
        try{
            System.out.println("entered into call service method 2");
            **response = httpclient.execute(httppost);**
            System.out.println("entered into call service method 3");

Answer 1

您是否在单独的Thread / AsyncTask中调用此函数？如果您的应用中经常使用请求，我还建议您考虑使用服务。

这是一个适用于我的POST方法，但不要忘记以某种方式异步调用它：

public void executePost(String url, List<NameValuePair> postParams) {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(url);
    InputStream is = null;
    try {
        httppost.setEntity(new UrlEncodedFormEntity(postParams));
        HttpResponse response = httpclient.execute(httppost);
        if (response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
            HttpEntity entity = response.getEntity();
            if (entity != null) {
                is = entity.getContent();
                ByteArrayOutputStream bos = new ByteArrayOutputStream();
                int inChar;
                while ((inChar = is.read()) != -1) {
                    bos.write(inChar);
                }

                String resp = bos.toString();
                // report back the resp e.g. via LocalBroadcast message 
            } else {
                // report back e.g. via LocalBroadcast message 
            }
        }
        else {
            // report back e.g. via LocalBroadcast message 
        }
    } catch (Exception e) {
            // report back the exception e.g. via LocalBroadcast message 
        // exception message: e.getMessage()
    } finally {
        if (is != null) {
            try {
                is.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }
}

httpclient.execute没有给出结果既不例外

1 个答案: