我有一个搜索方法,它接收用户输入的字符串,在每个空格字符处拆分它,然后根据分隔的字词列表继续查找匹配项:
string[] terms = searchTerms.ToLower().Trim().Split( ' ' );
现在我已经获得了进一步的要求:能够通过双引号分隔符来搜索短语。因此,如果提供的搜索字词是:
“一行”文字
搜索将匹配“一行”和“文本”的出现,而不是四个单独的术语[在搜索之前还需要删除打开和关闭的双引号]。
如何在C#中实现这一目标?我会假设正则表达式是要走的路,但是没有涉足它们,所以不知道它们是否是最好的解决方案。
如果您需要更多信息,请询问。在此先感谢您的帮助。
答案 0 :(得分:2)
这是一个正则表达式模式,它将返回名为“term
”的组中的匹配项:
("(?<term>[^"]+)"\s*|(?<term>[^ ]+)\s*)+
所以对于输入:
"a line" of text
“term
”群组标识的输出项目为:
a line
of
text
答案 1 :(得分:1)
正则表达式肯定是要走的路......
您应该检查此MSDN链接以获取有关Regex类的一些信息: http://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex.aspx
这是学习一些正则表达式语法的优秀链接: http://www.radsoftware.com.au/articles/regexlearnsyntax.aspx
然后,为了添加一些代码示例,您可以按照以下方式进行操作:
string searchString = "a line of";
Match m = Regex.Match(textToSearch, searchString);
或者如果您只是想知道字符串是否包含匹配项:
bool success = Regex.Match(textToSearch, searchString).Success;
答案 2 :(得分:1)
答案 3 :(得分:1)
使用Regexs ....
string textToSearchIn =“”一行“text”;
string result = Regex.Match(textToSearchIn,“(?&lt; =”)。*?(?=“)”)。值;
或者如果多于一个,请将其放入匹配集合中......
MatchCollection allPhrases = Regex.Matches(textToSearchIn,“(?&lt; =”)。*?(?=“)”);
答案 4 :(得分:0)
Knuth-Morris-Pratt(KMP算法)被认为是在字符串中查找子串的最快算法(好吧,技术上不是字符串而是字节数组)。
using System.Collections.Generic;
namespace KMPSearch
{
public class KMPSearch
{
public static int NORESULT = -1;
private string _needle;
private string _haystack;
private int[] _jumpTable;
public KMPSearch(string haystack, string needle)
{
Haystack = haystack;
Needle = needle;
}
public void ComputeJumpTable()
{
//Fix if we are looking for just one character...
if (Needle.Length == 1)
{
JumpTable = new int[1] { -1 };
}
else
{
int needleLength = Needle.Length;
int i = 2;
int k = 0;
JumpTable = new int[needleLength];
JumpTable[0] = -1;
JumpTable[1] = 0;
while (i <= needleLength)
{
if (i == needleLength)
{
JumpTable[needleLength - 1] = k;
}
else if (Needle[k] == Needle[i])
{
k++;
JumpTable[i] = k;
}
else if (k > 0)
{
JumpTable[i - 1] = k;
k = 0;
}
i++;
}
}
}
public int[] MatchAll()
{
List<int> matches = new List<int>();
int offset = 0;
int needleLength = Needle.Length;
int m = Match(offset);
while (m != NORESULT)
{
matches.Add(m);
offset = m + needleLength;
m = Match(offset);
}
return matches.ToArray();
}
public int Match()
{
return Match(0);
}
public int Match(int offset)
{
ComputeJumpTable();
int haystackLength = Haystack.Length;
int needleLength = Needle.Length;
if ((offset >= haystackLength) || (needleLength > ( haystackLength - offset)))
return NORESULT;
int haystackIndex = offset;
int needleIndex = 0;
while (haystackIndex < haystackLength)
{
if (needleIndex >= needleLength)
return haystackIndex;
if (haystackIndex + needleIndex >= haystackLength)
return NORESULT;
if (Haystack[haystackIndex + needleIndex] == Needle[needleIndex])
{
needleIndex++;
}
else
{
//Naive solution
haystackIndex += needleIndex;
//Go back
if (needleIndex > 1)
{
//Index of the last matching character is needleIndex - 1!
haystackIndex -= JumpTable[needleIndex - 1];
needleIndex = JumpTable[needleIndex - 1];
}
else
haystackIndex -= JumpTable[needleIndex];
}
}
return NORESULT;
}
public string Needle
{
get { return _needle; }
set { _needle = value; }
}
public string Haystack
{
get { return _haystack; }
set { _haystack = value; }
}
public int[] JumpTable
{
get { return _jumpTable; }
set { _jumpTable = value; }
}
}
}
用法: -
using System;
using System.Collections.Generic;
using System.Text;
using System.Reflection;
namespace KMPSearch
{
class Program
{
static void Main(string[] args)
{
if (args.Length != 2)
{
Console.WriteLine("Usage: " + Environment.GetCommandLineArgs()[0] + " haystack needle");
}
else
{
KMPSearch search = new KMPSearch(args[0], args[1]);
int[] matches = search.MatchAll();
foreach (int i in matches)
Console.WriteLine("Match found at position " + i+1);
}
}
}
}
答案 5 :(得分:0)
试试这个,它会返回一个文本数组。例如:{“一行”文字“记事本”}:
string textToSearch = "\"a line of\" text \" notepad\"";
MatchCollection allPhrases = Regex.Matches(textToSearch, "(?<=\").*?(?=\")");
var RegArray = allPhrases.Cast<Match>().ToArray();
输出:{“一行”,“文字”,“记事本”}