R中的2色热图，中间色固定到特定值

Question

这个热图图像是在Excel中生成的，但是当我正在尝试学习R时，我想知道如何使用R制作热像图。

现在，这段代码正在运行，但并不像预期的那样......

(p <- ggplot(melt(heat), aes(Var2, Var1))
 + geom_tile(aes(fill = value), colour = "white")
 + scale_fill_gradient(low = "red", high = "green"))

我想要2个渐变，绿色（最高值）到白色（数字1000）到红色（最低值）。是否有可能在R？

热数据集：

> heat[0:10,0:10]
          [,1]     [,2]      [,3]      [,4]      [,5]      [,6]      [,7]      [,8]      [,9]     [,10]
 [1,] 1000.000    0.000    0.0000    0.0000  757.0317  709.3896  843.7676  932.2801    0.0000 1016.7203
 [2,] 1087.658 1000.000    0.0000    0.0000  935.5829  854.5110  889.5042 1091.4610  929.1611    0.0000
 [3,] 1181.599 1361.953 1000.0000    0.0000    0.0000 1102.1590 1147.1300  984.1374  969.0718 1058.3456
 [4,] 1319.012 1405.954 1187.5215 1000.0000    0.0000 1093.8854 1195.7298 1077.0797 1119.4640 1159.5207
 [5,]    0.000    0.000  909.1927  817.5097 1000.0000    0.0000 1101.2891 1064.6516 1037.1623  990.3974
 [6,]    0.000    0.000    0.0000    0.0000  887.7498 1000.0000 1015.9835 1062.1668 1105.2163  983.2319
 [7,]    0.000    0.000    0.0000    0.0000    0.0000    0.0000 1000.0000  911.0699 1026.1989  951.3572
 [8,]    0.000    0.000    0.0000    0.0000    0.0000    0.0000    0.0000 1000.0000  834.8725  927.6802
 [9,] 1261.824    0.000    0.0000    0.0000    0.0000    0.0000    0.0000    0.0000 1000.0000  795.6285
[10,]    0.000 1121.210    0.0000    0.0000    0.0000    0.0000    0.0000    0.0000    0.0000 1000.0000

Answer 1

您可以使用？scale_fill_gradientn

给你重视：

  library(scales)
  heat.dat <- heat[0:10,0:10]
  dat <- expand.grid(var1=1:10, var2=1:10)
  dat$value <- melt(heat.dat)$value
  ggplot(dat, aes(x=var1,y=var2))+ 
        geom_tile(aes(fill = value),colour='white')+
        scale_fill_gradientn(colours=c("red","white","green"),
         values  = rescale(c(min(dat$value), 1000, max(dat$value)))

使用莱迪思：

with(dat,
levelplot(round(value,0)~y*x, 
          dat, 
          panel=function(...) {
                 arg <- list(...)
                 panel.levelplot(...)
                 panel.text(arg$x, arg$y,arg$z)},
          scales = list(y = list(at=y,labels=y),
                        x = list(at=y,labels=y)),
          col.regions = colorRampPalette(c("red", "white", "green"),interpolate ='spline'))
)

Answer 2

除了agstudy的答案和评论之外，您还可以使用纯ggplot语法并通过label在aes（）中映射标签：

    heat=structure(c(1000, 1087.658, 1181.599, 1319.012, 0, 0, 0, 0, 261.824,0, 0, 1000, 1361.953, 1405.954, 0, 0, 0, 0, 0, 1121.21, 0, 0,1000, 187.5215, 909.1927, 0, 0, 0, 0, 0, 0, 0, 0, 1000, 817.5097,0, 0, 0, 0, 0, 57.0317, 935.5829, 0, 0, 1000, 887.7498, 0, 0,0, 0, 709.3896, 854.511, 1102.159, 093.8854, 0, 1000, 0, 0,0, 0, 843.7676, 889.5042, 1147.13, 1195.7298, 1101.2891, 015.9835,1000, 0, 0, 0, 932.2801, 1091.461, 984.1374, 1077.0797, 1064.6516,1062.1668, 911.0699, 1000, 0, 0, 0, 929.1611, 969.0718, 1119.464,1037.1623, 1105.2163, 1026.1989, 834.8725, 1000, 0, 1016.7203,0, 058.3456, 1159.5207, 990.3974, 983.2319, 951.3572, 927.6802,795.6285, 1000), Dim  c(10L, 10L), .Dimnames = list(NULL, NULL))

    heat_melted = reshape2::melt(heat[10:0,0:10])

    ggplot(heat_melted, aes(Var2, Var1, label = round(value))) +   
    geom_tile(aes(fill = value),  colour = "white") +   
    scale_fill_gradientn(colours=c("red", "white", "green"), 
    values=rescale(c(min(heat_melted$value), 1000, max(heat_melted$value))), guide="colorbar") +
    geom_text()

plot