我编写了一个tic tac toe游戏，它编译并运行良好，但是如果你点击左上角的框，它会自动说X赢得Like this。这是董事会唯一能做到这一点的运动。不确定在确定获胜者时我做错了什么。如果您想要查看更多代码，则完整代码为here。
//Determine who won
if(button1.getText() == button2.getText()
&& button2.getText() == button3.getText()
&& button1.getText() != "")
{
win = true;
}
else if(button4.getText() == button5.getText()
&& button5.getText() == button6.getText()
&& button4.getText() != "")
{
win = true;
}
else if(button7.getText() == button8.getText()
&& button8.getText() == button9.getText()
&& button7.getText() != "")
{
win = true;
}
else if(button1.getText() == button4.getText()
&& button4.getText() == button7.getText()
&& button1.getText() != "")
{
win = true;
}
else if(button2.getText() == button5.getText()
&& button5.getText() == button8.getText()
&& button2.getText() != "")
{
win = true;
}
else if(button3.getText() == button6.getText()
&& button6.getText() == button9.getText()
&& button3.getText() != "")
{
win = true;
}
else if(button1.getText() == button5.getText()
&& button5.getText() == button9.getText()
&& button1.getText() != "")
{
win = true;
}
else if(button3.getText() == button5.getText()
&& button5.getText() == button7.getText()
&& button1.getText() != "")
{
win = true;
}
else
{
win = false;
}
if (win == true)
{
JOptionPane.showMessageDialog(null,
letter + " Wins!");
}
else if (count == 9 && win == false)
{
JOptionPane.showMessageDialog(null,
"Tie Game!");
}
}
}