我正在开发一些工作流程,可能会引发许多例外情况。我听说我们可以在Enum(Exception1,Exception2 ......)中保留所有可能的异常并使用它。我们怎样才能在Java中使用Enums?
答案 0 :(得分:1)
您可以使用
添加例外类enum EnumWithExceptions {
ENUM1(Exception1.class, Exception2.class),
ENUM2(Exception3.class);
private final Class<? extends Exception>[] exceptions;
private EnumWithExceptions(Class<? extends Exception>... exceptions) {
this.exceptions = exceptions;
}
public boolean matches(Exception e) {
for(Class<? extends Exception> e2: exceptions)
if (e2.isInstance(e)) return true;
return false;
}
}
} catch(Exception e){
if (ENUM1.matches(e)){
//do something
} else if(ENUM2.matches(e)) {
//do something
} else {
//do something
}
}
答案 1 :(得分:1)
enum Fred {
SAM(AnException.class),
I(AnotherException.class),
AM(YetAnotherException.class)
;
private Throwable t;
Fred(Throwable throwable) {
this.t = throwable;
}
public Throwable getThrowable() {
return t;
}
}
...
throw Fred.SAM.getThrowable();
答案 2 :(得分:0)
为什么不将异常存储在ArrayList中?或者,如果要为索引命名,可以使用HashMap。
import java.util.ArrayList;
import java.util.HashMap;
public final class ExceptionStorage {
private static int exceptionCount = 0;
private static HashMap<String, Exception> indexedExceptions = new HashMap<>();
private static ArrayList<Exception> exceptions = new ArrayList();
public static void addException(Exception e) {
exceptions.add(e);
}
public static void putException(Exception e) {
indexedExceptions.put("Exception" + (++exceptionCount), e);
}
public static ArrayList<Exception> getUnindexedExceptions() {
return this.exceptions;
}
public static HashMap<String, Exception> getIndexedExceptions() {
return this.indexedExceptions;
}
}