Question

我对使用Transaction进行异常处理有疑问。为了清楚说明我的问题，我想展示我的配置：

<bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
    <property name="sessionFactory" ref="sessionFactory" />
</bean>

<tx:annotation-driven transaction-manager="transactionManager" />

<bean id="transactionInterceptor" abstract="true" class="org.springframework.transaction.interceptor.TransactionProxyFactoryBean">
    <property name="transactionManager" ref="transactionManager" />
    <property name="transactionAttributeSource">
        <bean class="org.springframework.transaction.annotation.AnnotationTransactionAttributeSource" />
    </property>
</bean>

<bean id="baseService" abstract="true">
    <property name="daoProvider" ref="daoProvider" />
</bean>

<bean id="customerService" parent="transactionInterceptor">
    <property name="target">
        <bean class="com.edfx.adb.service.CustomerService" parent="baseService" />
    </property>
</bean>

<bean id="daoProvider" class="com.edfx.adb.dao.provider.DaoProvider">   
    <property name="customerDao" ref="customerDao" />
</bean>

<bean id="customerDao" class="com.edfx.adb.dao.CustomerDao">
    <constructor-arg value="#{T(com.edfx.adb.persist.entity.Customer)}" />
    <property name="sessionFactory" ref="sessionFactory" />
</bean>

活动交易类是：

@Transactional
public class CustomerService extends BaseService implements ICustomerService {

    @Transactional(readOnly = true)
    public Customer getCustomerById(String id) {
        return getDaoProvider().getCustomerDao().getCustomerById(id);
    }

    @Transactional(readOnly = false, propagation = Propagation.REQUIRED, rollbackFor = { Throwable.class })
    public void addNewCustomer(CustomerDTO customerDTO) {
        Customer customer = new Customer();

        customer.setCustomerId(customerDTO.getCustomerId());
        customer.setCustomerName(customerDTO.getCustomerName());
        customer.setActive(customerDTO.isActive());

        getDaoProvider().getCustomerDao().save(customer);
    }
}

我的疑问在于方法addNewCustomer。我已设置rollbackFor = { Throwable.class }。

它是如何运作的？

我还需要显式处理异常，如：

@Transactional(readOnly = false, propagation = Propagation.REQUIRED, rollbackFor = { Throwable.class })
public boolean addNewCustomer(CustomerDTO customerDTO) {
    Customer customer = new Customer();

    customer.setCustomerId(customerDTO.getCustomerId());
    customer.setCustomerName(customerDTO.getCustomerName());
    customer.setActive(customerDTO.isActive());

    try {
        getDaoProvider().getCustomerDao().save(customer);
    } catch (Throwable throwable) {
        return false;
    }

    return true;
}

强制我通过删除customer表中的列来创建异常，但是try-catch块中没有捕获异常，而是我可以从我调用{{1}的托管bean中捕获该异常方法。

Answer 1

这是Spring docs的摘录

在其默认配置中，Spring Framework的事务基础结构代码仅标记用于回滚的事务运行时，未经检查的异常;也就是抛出异常的时候是RuntimeException的实例或子类。（错误也将 - 通过 default - 导致回滚）。检查抛出的异常从事务方法不会导致默认回滚配置。

你设置rollbackFor = Throwable.class，现在Spring将回滚任何异常/错误。默认情况下，无论我们是否喜欢，Spring将仅针对RuintimeException进行回滚，否则提交

Answer 2

Spring框架只抛出RuntimeExceptions，从技术上讲，你永远不必捕获任何异常。

Spring Transaction中是否需要异常处理？

2 个答案: