Question

所以目前我有两个mysql tabales之间的关系：带有“id”和“content”的 wp_bp_activity 和带有“activity_id”的 wp_bp_activity_meta ，这将匹配wp_bp_activity id和“meta_value” 我正在尝试根据wp_bp_activity_meta - ＆gt;的文本输出meta_value wp_bp_activity - ＆gt;内容wp_bp_activity - ＆gt; id = wp_bp_activity_meta - ＆gt; ACTIVITY_ID 不确定即使是这样的事也是可能的。我卡住了！这是我现在的代码：

$ query =“SELECT * FROM wp_bp_activity_meta WHERE meta_value LIKE'test'”;

Answer 1

SELECT  a.*, b.*
FROM    wp_bp_activity a
        INNER JOIN wp_bp_activity_meta b
            ON CONCAT(a.id, a.meta_value) = b.activity_id

Answer 2

$query = "SELECT *
FROM wp_bp_activity_meta
INNER JOIN wp_bp_activity
ON wp_bp_activity.if = wp_bp_activity_meta.activity_id
WHERE meta_value LIKE 'test' ";

在mysql上连接两个表

2 个答案: