Question

我有一些带有一些数据的未排序数组，我想创建新的数组宽度排序数据：

   var gridData = [], i = -1;
        while (i++ < 5) {
                gridData[i] = {
                    "ProjectOwner": ["Corporation1","Corporation2","Corporation3"][i % 2],
                    "ProjectId": i,
                    "ProjectName": String.fromCharCode("A".charCodeAt(0) + i % 3) + (1 + i % 3),
                    "ProjectType": ["Conference","Programming","Research","Conference"][i % 4],
                    "ProjectLeader": "Name1Name2Name3".substr(i % 3 * 5,5) + " " + "Surname1Surname2Surname3".substr(i % 3 * 8,8),
                    "StartDate": new Date(2009 + i % 4 % 2, (i + 3) % 12, 5 + i * 4 % 24).toLocaleDateString(),
                    "EndDate": new Date(2010 + i % 4 % 2, (i + 3) % 12, 5 + i * 4 % 24).toLocaleDateString(),
                    "Summary": "bla bla"
                };
            }

未排序的数据看起来像对象数组

我希望将其归类为

//First group by ProjectOwner
Object {Corporation1: Array[3], Corporation2: Array[3]}
   //Second group by ProjectName
   Corporation1: Array[x]
            A1 : Array [x]
                 Object1
                 Object2
                 ...
   Corporation2: Array[x]

依旧...... 我已经尝试过array.map和reduce，但它们似乎不适用于IE 我也试过了：

$.each(aggregation_content, function(i,aggr) {

    $.each(_newData, function(a, objA) {
        if(i > 0)
            o = _newData[a][aggregation_content[i - 1].cell];
        n = _newData[a][aggregation_content[i].cell];

        if(typeof o == "undefined") //For first row when new Data is empty array
        {
            if(! (n in newData))
                newData[n] = [];
            newData[n].push(objA);
        }
    })})
console.log(newData);

其中aggregation_content是

{cell:"ProjectOwner",value:""},{cell:"ProjectName",value:""},{cell:"ProjectLeader",value:""},{cell:"ProjectType",value:""}

并且新数据从一开始就是gridData。这适用于第一个聚合。但问题是当我聚合数组newData时我需要使用

if(! (n in newData[o]))
    newData[o][n] = [];
 newData[o][n].push(objA);

并且[o]应该是[n] -node的父级。 ok-第二组也可以使用该代码，但是当我想制作5个内部组时，我需要像

那样做

newData["firstGroup"]["secondGroup"]["thirdGroup"]...[n].push("Some content").

如何以编程方式进行此操作？如果我做

newData = newData[o] - no good
or
temp = newData
do something to temp
newData[o] = temp not good eather :'(

我希望我写出可理解的文字：D

____ Edited_2012_12_13 ______________________________________

所以输入数据是

[Object, Object, Object, Object, Object, Object]
  0: Object
   EndDate: "Monday, April 05, 2010"
   ProjectId: 0
   ProjectLeader: "Name1 Surname1"
   ProjectName: "A1"
   ProjectOwner: "Corporation1"
   ProjectType: "Conference"
   StartDate: "Sunday, April 05, 2009"
   Summary: "bla bla"
   __proto__: Object
 1: Object
   EndDate: "Monday, May 09, 2011"
   ProjectId: 1
   ProjectLeader: "Name2 Surname2"
   ProjectName: "B2"
   ProjectOwner: "Corporation2"
   ProjectType: "Programming"
   StartDate: "Sunday, May 09, 2010"
   Summary: "bla bla"
   __proto__: Object
 2: Object
   ...
 3: Object
    ...
 4: Object
    ...
 5: Object
    ....

输出数据应该类似于

Object {Corporation1: Array[3], Corporation2: Array[3]}
 Corporation1: Array[2]
   0: A1:  Array[X]
         0: Object
            EndDate: "Monday, May 09, 2011"
            ProjectId: 1
            ProjectLeader: "Name2 Surname2"
            ProjectName: "A1"
            ProjectOwner: "Corporation2"
            ProjectType: "Programming"
            StartDate: "Sunday, May 09, 2010"
            Summary: "bla bla"
         1: Object
            ...
            ...
   1: B2:  Array[X]
         0: Object
            EndDate: "Monday, May 09, 2011"
            ProjectId: 1
            ProjectLeader: "Name2 Surname2"
            ProjectName: "B2"
            ProjectOwner: "Corporation2"
            ProjectType: "Programming"
            StartDate: "Sunday, May 09, 2010"
            Summary: "bla bla"
         1: Object
            ...
            ...
 Corporation2: Array[2]
   0: A1:  Array[X]
         0: Object
            EndDate: "Monday, May 09, 2011"
            ProjectId: 1
            ProjectLeader: "Name2 Surname2"
            ProjectName: "A1"
            ProjectOwner: "Corporation2"
            ProjectType: "Programming"
            StartDate: "Sunday, May 09, 2010"
            Summary: "bla bla"
         1: Object
            ...
            ...
   1: B2:  Array[X]
         0: Object
            EndDate: "Monday, May 09, 2011"
            ProjectId: 1
            ProjectLeader: "Name2 Surname2"
            ProjectName: "B2"
            ProjectOwner: "Corporation2"
            ProjectType: "Programming"
            StartDate: "Sunday, May 09, 2010"
            Summary: "bla bla"
         1: Object
            ...
            ...

树视图应该是两个或多个嵌套节点。

Answer 1

我之前遇到过类似的情况。我写了一个库来做到这一点：

https://github.com/raghavv/array-mod

请检查一下。我不是在推广我的图书馆，但我认为它符合您的要求。

此外，对于较旧的浏览器支持IE＆lt; 9.您还需要包括另一个优秀的图书馆：

https://github.com/kriskowal/es5-shim/

以下是如何获得第一组数组：

$（gridData）.findAll（“Corporation1”，“ProjectOwner”）;
  $（gridData）.findAll（“Corporation2”，“ProjectOwner”）;
  $（gridData）.findAll（“A1”，“ProjectName”）;
  $（gridData）.findAll（“B2”，“ProjectName”）;

Answer 2

我想出了这个结果：

this.groupBy = function(originalData, aggregation_content) 
    {
        var parentNode,node,i,j,g;
        var newData = {},temp;
        this.array.sortedData = originalData;
        $.each(aggregation_content,function(i,objI){
            $.each(originalData.Items,function(j,objJ){
                node = originalData.Items[j].GetValue(aggregation_content[i].column).replace(/\W+/gi,"");
                if(i > 0)
                {
                    temp = newData;
                    $.each(aggregation_content,function(g,objG){
                        parentNode = originalData.Items[j].GetValue(aggregation_content[g].column).replace(/\W+/gi,"");
                        if(!temp[parentNode])
                        {   
                            temp[parentNode] = [];
                        }
                        temp = temp[parentNode];
                    });
                    temp.push(objJ);
                }
                else
                {
                    if(!newData[node])
                        newData[node] = [];
                }
            });
        });
        console.log(newData);
        return newData;           
    }

我所做的是使用指针填充新的treeview（multidimencional）数组。所以输出按aggregation_content分组。

Answer 3

使用循环计数器根据长度分组：

var foo = [57657,57751,58401,58420,58588,58655,59238,59443,59488,59492,59570,59706,59924,59925, 57674, 57687, 57688, 57689, 57693, 57770, 57785, 57786, 57796, 57798, 57810, 57827, 57829, 57835, 57850, 57851, 57852, 57903, 57909, 57910,57957, 57972, 57998, 58022, 58046, 58059, 58064, 58077, 58085, 58097, 58103, 58105, 58127, 58138, 58139, 58220, 58320, 58353, 58356, 58357,58358, 58359, 58360, 58402, 58403, 58404, 58467, 58472, 58473, 58493, 58605]


/* Group into sets of twenty */
var i = 0; while (i <= foo.length) { Math[i] = foo.slice(i, i+20).toString(); i = i + 20; }

Javascript数组：如何分组

3 个答案: