我有这个示例数据并将其转换为如下所示的对象数组。这有两个级别:Level1和Level2。
var array = [{
"Level1": "Assigned to",
"Level2": "Assigned To 1"
}, {
"Level1": "Assigned to",
"Level2": "Assigned To 2"
}, {
"Level1": "Assigned to",
"Level2": "Assigned To 3"
}, {
"Level1": "Location1",
"Level2": "SubLocation 1"
}, {
"Level1": "Location1",
"Level2": "SubLocation 2"
}];
我想用它们的键对它进行分组,下面是密钥的名称/值。 (见下面的样本)。我将如何解决这个问题,以便在我的HTML中实现。
<div id="accordion">
<h3>Assigned to</h3>
<div>
<p>Assigned To 1</p>
<p>Assigned To 2</p>
<p>Assigned To 3</p>
</div>
<h3>Location</h3>
<div>
<p>SubLocation 1</p>
<p>SubLocation 2</p>
</div>
</div>
答案 0 :(得分:1)
使用$.each()
,您可以迭代数组并获取值,然后操纵它们。
var json = [{
"Level1": "Assigned to",
"Level2": "Assigned To 1"
}, {
"Level1": "Assigned to",
"Level2": "Assigned To 2"
}, {
"Level1": "Assigned to",
"Level2": "Assigned To 3"
}, {
"Level1": "Location1",
"Level2": "SubLocation 1"
}, {
"Level1": "Location1",
"Level2": "SubLocation 2"
}];
var LevelArray = []
$.each(json, function(i, val){
//console.log(val);
var className = val.Level1.replace(/\s/g);
if($.inArray(className, LevelArray) == -1){
LevelArray.push(className);
var thisLevel = $('<div>',{
'class' : className
});
thisLevel.append($('<h3>').text(val.Level1));
var thisRow = $('<div>').append($('<p>').text(val.Level2));
thisLevel.append(thisRow);
$('body').append(thisLevel);
} else {
var thisLevel = $('.' + className )
thisLevel.find('div').append($('<p>').text(val.Level2));
}
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>