我从通用的问题/答案数据中获取名称和地址数据,以创建某种规范化的报告数据库。
我得到的查询使用group_concat,适用于各组问题但不适用于多组问题。
我试图通过使用forename和surname以及仅3条记录来简化我正在做的事情,2个用于1个人,1个用于另一个。实际上,虽然有超过300,000条记录。
Example qs.Id = 1
的结果。
QuestionSetId Forename Surname
-------------------------------------------------------
1 Bob Jones
Example qs.Id IN (1, 2, 3)
的结果。
QuestionSetId Forename Surname
-------------------------------------------------------
3 Bob,Bob,Frank Jones,Jones,Smith
我希望qs.Id IN (1, 2, 3)
看到什么。
QuestionSetId Forename Surname
-------------------------------------------------------
1 Bob Jones
2 Bob Jones
3 Frank Smith
那么如何让第二个示例为每组名称和地址信息返回一个单独的行?
我意识到数据存储的当前方式是“有问题的”,但是我无法改变数据的存储方式。
我可以sets of individual answers但不知道如何结合其他人。
我无法更改的简化架构:
CREATE TABLE StaticQuestion (
Id INT NOT NULL,
StaticText VARCHAR(500) NOT NULL);
CREATE TABLE Question (
Id INT NOT NULL,
Text VARCHAR(500) NOT NULL);
CREATE TABLE StaticQuestionQuestionLink (
Id INT NOT NULL,
StaticQuestionId INT NOT NULL,
QuestionId INT NOT NULL,
DateEffective DATETIME NOT NULL);
CREATE TABLE Answer (
Id INT NOT NULL,
Text VARCHAR(500) NOT NULL);
CREATE TABLE QuestionSet (
Id INT NOT NULL,
DateEffective DATETIME NOT NULL);
CREATE TABLE QuestionAnswerLink (
Id INT NOT NULL,
QuestionSetId INT NOT NULL,
QuestionId INT NOT NULL,
AnswerId INT NOT NULL,
StaticQuestionId INT NOT NULL);
仅有姓名和姓氏的一些示例数据。
INSERT INTO StaticQuestion (Id, StaticText)
VALUES (1, 'FirstName'),
(2, 'LastName');
INSERT INTO Question (Id, Text)
VALUES (1, 'What is your first name?'),
(2, 'What is your forename?'),
(3, 'What is your Surname?');
INSERT INTO StaticQuestionQuestionLink (Id, StaticQuestionId, QuestionId, DateEffective)
VALUES (1, 1, 1, '2001-01-01'),
(2, 1, 2, '2008-08-08'),
(3, 2, 3, '2001-01-01');
INSERT INTO Answer (Id, Text)
VALUES (1, 'Bob'),
(2, 'Jones'),
(3, 'Bob'),
(4, 'Jones'),
(5, 'Frank'),
(6, 'Smith');
INSERT INTO QuestionSet (Id, DateEffective)
VALUES (1, '2002-03-25'),
(2, '2009-05-05'),
(3, '2009-08-06');
INSERT INTO QuestionAnswerLink (Id, QuestionSetId, QuestionId, AnswerId, StaticQuestionId)
VALUES (1, 1, 1, 1, 1),
(2, 1, 3, 2, 2),
(3, 2, 2, 3, 1),
(4, 2, 3, 4, 2),
(5, 3, 2, 5, 1),
(6, 3, 3, 6, 2);
以防SQLFiddle在这里是我链接到的示例中的3个查询:
1: - 工作查询但仅限于1组数据。
SELECT MAX(QuestionSetId) AS QuestionSetId,
GROUP_CONCAT(Forename) AS Forename,
GROUP_CONCAT(Surname) AS Surname
FROM (SELECT
x.QuestionSetId,
CASE x.StaticQuestionId WHEN 1 THEN Text END AS Forename,
CASE x.StaticQuestionId WHEN 2 THEN Text END AS Surname
FROM (SELECT (SELECT link.StaticQuestionId
FROM StaticQuestionQuestionLink link
WHERE link.Id = qa.QuestionId
AND link.DateEffective <= qs.DateEffective
AND link.StaticQuestionId IN (1, 2)
ORDER BY link.DateEffective DESC LIMIT 1) AS StaticQuestionId,
a.Text,
qa.QuestionSetId
FROM QuestionSet qs
INNER JOIN QuestionAnswerLink qa ON qs.Id = qa.QuestionSetId
INNER JOIN Answer a ON qa.AnswerId = a.Id
WHERE qs.Id IN (1)) x) y
2: - 工作查询,但对多组数据产生不良后果。
SELECT MAX(QuestionSetId) AS QuestionSetId,
GROUP_CONCAT(Forename) AS Forename,
GROUP_CONCAT(Surname) AS Surname
FROM (SELECT
x.QuestionSetId,
CASE x.StaticQuestionId WHEN 1 THEN Text END AS Forename,
CASE x.StaticQuestionId WHEN 2 THEN Text END AS Surname
FROM (SELECT (SELECT link.StaticQuestionId
FROM StaticQuestionQuestionLink link
WHERE link.Id = qa.QuestionId
AND link.DateEffective <= qs.DateEffective
AND link.StaticQuestionId IN (1, 2)
ORDER BY link.DateEffective DESC LIMIT 1) AS StaticQuestionId,
a.Text,
qa.QuestionSetId
FROM QuestionSet qs
INNER JOIN QuestionAnswerLink qa ON qs.Id = qa.QuestionSetId
INNER JOIN Answer a ON qa.AnswerId = a.Id
WHERE qs.Id IN (1, 2, 3)) x) y
3: - 仅在1个字段(答案)上对多组数据进行查询。
SELECT
qs.Id AS QuestionSet,
a.Text AS Answer
FROM
QuestionSet qs
INNER JOIN QuestionAnswerLink qalink ON qs.Id = qalink.QuestionSetId
INNER JOIN StaticQuestionQuestionLink sqqlink ON qalink.QuestionId = sqqlink.QuestionId
INNER JOIN Answer a ON qalink.AnswerId = a.Id
WHERE
sqqlink.StaticQuestionId = 1 /* FirstName */
AND sqqlink.DateEffective =
(SELECT DateEffective
FROM StaticQuestionQuestionLink
WHERE StaticQuestionId = 1
AND DateEffective <= qs.DateEffective
ORDER BY DateEffective
DESC
LIMIT 1)
答案 0 :(得分:3)
@PeteGo,试试这个
SELECT
qs.Id AS QuestionSet,
GROUP_CONCAT(a.Text SEPARATOR ', ') AS Answer
FROM
QuestionSet qs
INNER JOIN QuestionAnswerLink qalink ON qs.Id = qalink.QuestionSetId
INNER JOIN StaticQuestionQuestionLink sqqlink ON qalink.QuestionId = sqqlink.QuestionId
INNER JOIN Answer a ON qalink.AnswerId = a.Id
WHERE
sqqlink.StaticQuestionId in (1,2,3) /* FirstName */
GROUP BY qs.Id;
OR
SELECT
qs.Id AS QuestionSet,
group_CONCAT(b.Text ORDER BY b.Id ) AS Answer
FROM
QuestionSet qs
INNER JOIN QuestionAnswerLink qalink ON qs.Id = qalink.QuestionSetId
INNER JOIN StaticQuestionQuestionLink sqqlink ON qalink.QuestionId = sqqlink.QuestionId
INNER JOIN Answer a ON qalink.AnswerId = a.Id
INNER JOIN Answer b ON qalink.AnswerId = b.Id
WHERE
sqqlink.StaticQuestionId in (1,2,3)
group by qs.Id ;
OR
select qs.Id, group_concat(a.Text order by a.Id) from QuestionAnswerLink qalink
left join QuestionSet qs on qalink.QuestionSetId=qs.Id
left join Answer a on qalink.AnswerId = a.Id
left join QuestionSet qs1 on qalink.QuestionSetId=qs1.Id
left join Answer b on qalink.AnswerId = b.Id
group by qs.Id ;
答案 1 :(得分:2)
从@PixelMaker和@PeteGO偷窃,我会把这个扔进去
SELECT qs.Id AS QuestionSetId,
GROUP_CONCAT(a.Text order by a.id) AS Answer
FROM QuestionSet qs
JOIN QuestionAnswerLink qa ON qs.Id = qa.QuestionSetId
JOIN StaticQuestionQuestionLink link ON qa.QuestionId = link.QuestionId
JOIN Answer a ON qa.AnswerId = a.Id
WHERE link.Id = qa.QuestionId
AND link.DateEffective <= qs.DateEffective
AND link.StaticQuestionId IN (1, 2)
and qs.id in (1,2,3)
GROUP BY qs.Id
最后这一个SQL Fiddle
SELECT qs.Id AS QuestionSetId,
GROUP_CONCAT(case link.staticquestionid when 1 then a.Text end) AS forename,
GROUP_CONCAT(case link.staticquestionid when 2 then a.Text end) AS surname
FROM QuestionSet qs
JOIN QuestionAnswerLink qa ON qs.Id = qa.QuestionSetId
JOIN StaticQuestionQuestionLink link ON qa.QuestionId = link.QuestionId
JOIN Answer a ON qa.AnswerId = a.Id
WHERE link.Id = qa.QuestionId
AND link.DateEffective <= qs.DateEffective
AND link.StaticQuestionId IN (1, 2)
and qs.id in (1,2,3)
GROUP BY qs.Id
给出了期望的结果。