抱歉我的英语不好...... 我有一些桌子......
ORDERS
id int(11) NOT NULL AUTO_INCREMENT,
device_id mediumint(9) NOT NULL,
userid smallint(6) NOT NULL,
eta datetime DEFAULT NULL,
modified_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (id)
id device_id userid eta modified_at
1 1 1 2015-12-17 2015-12-17 00:00
2 1 3 2015-12-18 2015-12-17 00:00
3 2 1 2015-12-17 2015-12-17 00:00
DEVICES
id int(11) NOT NULL AUTO_INCREMENT,
custcode varchar(100) NOT NULL,
address text DEFAULT NULL,
serial varchar(20) NOT NULL COMMENT '012345678901234567890',
userid int(11) NOT NULL,
modified_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (id)
id custcode address serial userid modified_at
1 101101 Address 123456 1 2015-12-11 00:00
1 10568 Address 98756245 1 2015-12-10 00:00
CUSTOMERS
id int(11) NOT NULL AUTO_INCREMENT,
custcode varchar(10) NOT NULL,
custname varchar(255) DEFAULT NULL,
modified_at timestamp NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (id)
id custcode custname modified_at
1 101101 Customer 1 2015-12-11 00:00
2 10568 Customer 2 2015-12-11 00:00
USERS
id mediumint(8) UNSIGNED NOT NULL AUTO_INCREMENT,
username varchar(20) NOT NULL DEFAULT '',
email varchar(128) NOT NULL DEFAULT '',
fullname varchar(50) DEFAULT NULL,
phone varchar(12) DEFAULT NULL,
PRIMARY KEY (id)
id username email fullname phone
1 usr1 usr1@local 123
2 usr2 usr2@local 123
3 usr3 usr3@local 187
我选择所有订单的主要查询。
SELECT o.*, a.custcode, c.custname, a.address,
FROM orders o
LEFT JOIN devices a ON o.atm_id = a.id
LEFT JOIN customers c ON a.custcode = c.custcode
LEFT JOIN users u ON o.userid = u.id
WHERE o.userid IN (87)
ORDER BY o.modified DESC
工作正常，我会看到所有订单与设备等。 但是我需要为每个订单提供一些额外的信息......
再添加两个表：
ORDER_DATA
id int(11) NOT NULL AUTO_INCREMENT,
orders_id int(11) NOT NULL,
operdate date NOT NULL,
comment varchar(255) DEFAULT NULL,
userid int(11) NOT NULL,
distance float DEFAULT NULL,
PRIMARY KEY (id)
id orders_id operdate comment userid distance
1 1 2015-12-17 1 15
2 3 2015-12-17 1 150
3 1 2015-12-20 1 150
存储订单操作。白天进行一次操作，不再有。
ORDER_OPER
id int(11) NOT NULL AUTO_INCREMENT,
order_data int(11) NOT NULL,
order_type varchar(2) NOT NULL,
otime time NOT NULL,
modified_at timestamp NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (id)
id order_data order_type otime modified_at
1 1 Dispatched 10:00
2 1 Progress 11:00
3 1 Complete 15:30
4 2 Complete 14:00
5 3 Dispatched 09:00
6 3 Suspended 14:00
每个操作都有类型的操作。
好吧，现在我将此查询用于用户的选择顺序操作：
SELECT o1.orders_id, o1.operdate, o1.comment, o1.userid,
GROUP_CONCAT(oo.order_type, '#', TIME(oo.otime) ORDER BY oo.modified_at SEPARATOR ';') AS operations
FROM order_data o1
LEFT JOIN order_oper oo ON o1.id=oo.order_data
WHERE o1.orders_id=1 AND o1.operdate = DATE('2015-12-17')
GROUP BY o1.operdate
结果：
id operdate comment userid operations
1 17.12.2015 Job done! Device repaired. 1 Dispatched#10:00;Progress#11:00;Complete#15:30
最后我需要在主查询中进行操作。我怎样才能做到这一点？请帮我。 谢谢!!!!