Question

我有这张桌子：

idTransactions  idCampaignsList idMemberCard    amountOriginal  amountFinal   dateTransaction
1   2   1   50.00   100.00          2012-10-31 12:45:41
2   3   1   0.00    -50.00          2012-10-31 12:47:25
3   2   2   255.00  255.00          2012-10-31 17:19:07
4   1   2   95.00   95.00           2012-11-02 20:38:36
5   3   2   0.00    -400.00         2012-11-02 20:39:50
24  1   4   10.00   2.00            2012-11-03 11:16:3

使用此查询

SELECT  SUM(amountOriginal) AS euro,
SUM(amountFinal) AS deducted,
EXTRACT(YEAR_MONTH FROM(dateTransaction)) AS period
FROM transactions 
INNER JOIN campaignsList ON campaignsList.idCampaignsList = transactions.idCampaignsList 
INNER JOIN customers ON customers.idCustomer = campaignsList.idCustomer 
WHERE   customers.idCustomer = 14
        AND
        transactions.idCampaignsList = 2
GROUP BY period
ORDER BY period

我获得了这个结果

euro             deducted   period
305.00           305.00         201210
14860.46            -22758.50   201211
1845.00         -34710.00   201212

过去12个月，“收费”和已解除的总和。

现在，idCampaignsList可以是1,2，也就是500，它取决于我的idCustomer（通过JOIN检索）有多少“广告系列”。

我想要查询dinamic，“对于每个”idCampaignsList，打印amountOriginal和amountFinal的总和。

打算，从previos表，我想

idCampaignsList    SUM(amountOriginal)   SUM(amountFinal)  period
1                  50                    50                201210
2                  255                   255               201210
2                  95                    -305              201211
4                  10                    2                 201211

因此，对于每个句点，为每个不同的idCampaignsList汇总列，其中idCampaignsList是dinamically（SELECT idCampaignsList FROM myOtherTable，其中idCustomer = 14）

Answer 1

我想要查询dinamic，即“为每个”idCampaignsList打印我总和金额原始金额和金额最终。

我认为你所说的several For each是GROUP BY transactions.idCampaignsList。

尝试将transactions.idCampaignsList添加到SELECT列表，从transactions.idCampaignsList = 2子句中删除谓词WHERE，并将GROUP BY子句中的该列列为好吧，就像这样：

SELECT  
  transactions.idCampaignsList
  SUM(amountOriginal) AS euro,
  SUM(amountFinal) AS deducted,
  EXTRACT(YEAR_MONTH FROM(dateTransaction)) AS period
FROM transactions 
INNER JOIN campaignsList
        ON campaignsList.idCampaignsList = transactions.idCampaignsList 
INNER JOIN customers 
        ON customers.idCustomer = campaignsList.idCustomer 
WHERE customers.idCustomer = 14
GROUP BY period, transactions.idCampaignsList
ORDER BY period

MySQL查询有几个“为每个”

1 个答案: